Reputation: 31
I'm trying to solve whats probably an easy task, but I'm extremely new to this and don't quite have my head around working with arrays in a complex fashion. I'm trying to figure out if two inputs each corresponding numbers sum to the same number (for example with 123 and 321, 1+3 2+2 and 1+3 all equal 4).
The code I have so far has broken down each input into arrays, and I can sum those arrays into a third array, but I cant figure out how to check it with itself. Should I even bother with the 3rd array, and just figure out how to check the sums of the array in a loop?
public static void Main()
{
Console.Write("\n\n"); //begin user input
Console.Write("Check whether each cooresponding digit in two intigers sum to the same number or not:\n");
Console.Write("-------------------------------------------");
Console.Write("\n\n");
Console.Write("Input 1st number then hit enter: ");
string int1 = (Console.ReadLine());//user input 1
Console.Write("Input 2nd number: ");
string int2 = (Console.ReadLine());//user input 2
int[] numbers = new int[int1.ToString().Length]; //changing user inputs to strings for array
int[] numbers2 = new int[int2.ToString().Length];
for (int i = 0; i < numbers.Length; i++)
{
numbers[i] = int.Parse(int1.Substring(i, 1));//populating arrays
numbers2[i] = int.Parse(int2.Substring(i, 1));
}
int[] numbers3 = new int[numbers.Length];
for (int i = 0; i < numbers.Length; i++)
{
numbers3[i] = (numbers[i] + numbers2[i]);
}
}
}
Upvotes: 3
Views: 445
Reputation: 2204
You're 99% of the way there already. Just lose the third array and check each individual sum in your final loop.
bool isOK = numbers.Length = numbers2.Length && numbers.Length > 0;
if(isOK)
{
int expectedSum = numbers[0] + numbers2[0];
for (int i = 1; i < numbers.Length; i++)
{
var sum = (numbers[i] + numbers2[i]);
if(sum != expectedSum)
{
isOK = false;
break;
}
}
}
Console.WriteLine(isOk ? "Good job." : "You got some learning to do.");
Upvotes: 0
Reputation: 15314
You can create the collections on the fly...
bool isEqual = Console.ReadLine()
.ToCharArray()
.Select(i => Convert.ToInt32(i.ToString()))
.Zip(Console.ReadLine()
.ToCharArray()
.Select(i => Convert.ToInt32(i.ToString())),
(i, j) => new
{
First = i,
Second = j,
Total = i + j
})
.GroupBy(x => x.Total)
.Count() == 1;
The output will equal true if all elements add up to the same value...
Test cases:
Should succeed
12345
54321
Should fail
12345
55432
To understand the above query, lets break it up into sections.
// Here I'm just converting a string to an IEnumerable<int>, a collection of integers basically
IEnumerable<int> ints1 = Console.ReadLine()
.ToCharArray()
.Select(i => Convert.ToInt32(i.ToString()));
IEnumerable<int> ints2 = Console.ReadLine()
.ToCharArray()
.Select(i => Convert.ToInt32(i.ToString()));
// Zip brings together two arrays and iterates through both at the same time.
// I used an anonymous object to store the original values as well as the calculated ones
var zippedArrays = ints1.Zip(ints2, (i, j) => new
{
First = i, // original value from ints1
Second = j, // original values from ints2
Total = i + j // calculated value ints1[x] + ints2[x]
});
// if the totals are [4,4,4], the method below will get rid of the duplicates.
// if the totals are [4,3,5], every element in that array would be returned
// if the totals are [4,4,5], only [4,5] would be returned.
var distinctByTotal = zippedArrays.GroupBy(x => x.Total);
// So what does this tell us? if the returned collection has a total count of 1 item,
// it means that every item in the collection must have had the same total sum
// So we can say that every element is equal if the response of our method == 1.
bool isEqual = distinctByTotal.Count() == 1;
Upvotes: 2