CODEWITHSUNDEEP
pythoncomparisonlist-comprehension
Matt
Matt

Reputation: 189

Comparing each element of a list to their corresponding index in another

I have a list:

list1=[1,2,3,4,5,6]

I need to compare this to a series of other lists:

list2=[[0,0,0,0,0,0],[0,1,2,3,4,5],[2,2,2,2,2,2],[5,4,3,2,1,0]]

and flag any of these in which every value in list1 is greater than the value of its corresponding index in list2[n] i.e:

list1[0]>list2[n][0], list1[1]>list2[n][1], list1[2]>list2[n][2], list1[3]>list2[n][3], list1[4]>list2[n][4], list1[5]>list2[n][5]

Here, it should return TRUE, TRUE, FALSE, FALSE

list1 and list2[n] are always of the same length, but this length can differ.

Upvotes: 2

Views: 64

Answers (1)

Sunitha
Sunitha

Reputation: 12015

Use zip and list comprehension to get a pair of elements from list1 and list2[n] and then use all to check if for all pairs (x,y), x>y 

>>> list1=[1,2,3,4,5,6]
>>> list2=[[0,0,0,0,0,0],[0,1,2,3,4,5],[2,2,2,2,2,2],[5,4,3,2,1,0]]
>>> [all(x>y for x,y in zip(list1,lst)) for lst in list2]
[True, True, False, False]

If list1 and list2[n] are of unequal sizes, replace zip with itertools.zip_longest

>>> from itertools import zip_longest
>>> [all(x>y for x,y in zip_longest(list1,lst, fillvalue=0)) for lst in list2]
[True, True, False, False]

Upvotes: 5

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