CODEWITHSUNDEEP
php
Tim
Tim

Reputation: 901

php get URL of current file directory

Might be an easy question for you, but I'm breaking my head over this one.

I have a php file that needs to know it's current directory url to be able to link to something relative to itself.

For example, currently I know to get the current directory path instead of the url. When I use this I get the path:

realpath(__DIR__)

result:

/Applications/MAMP/htdocs/mysite/dir1/dir2/dir3

But this would be my desired result:

http://localhost:8888/dir1/dir2/dir3

Note that this is not the location of the current page. The page calls a file from "http://localhost:8888/dir1/dir2/dir3/myfile.php" And "myfile.php" has the script from above.

-- edit to elaborate more details -- Thanks for your answers. But I get that I need to add more detail.

Upvotes: 13

Views: 43516

Answers (6)

oleviolin
oleviolin

Reputation: 1043

Based on some of the comments above (with some editing) this code will get a link 'my_file.php' in the current directory and display it in the devtools console of a javascript program.

<?php 
$link= $_SERVER['REQUEST_SCHEME'].'://' . $_SERVER['HTTP_HOST']. substr($_SERVER['REQUEST_URI'], 0, strrpos($_SERVER['REQUEST_URI'], "/")) .'/my_file.php' ;

echo "console.log('$link')"
?>

the $_SERVER['REQUEST_SCHEME'] give you either 'http' or 'https'

Upvotes: 0

SDanielCH
SDanielCH

Reputation: 11

You can use this code for locate internal project directory

function baseURL(){
    if(isset($_SERVER['HTTPS']) && $_SERVER['HTTPS'] === 'on') {
        $url = "https://"; 
    }else{
        $url = "http://"; 
    }
    // Fix 
    if(dirname($_SERVER['PHP_SELF']) == "/" || dirname($_SERVER['PHP_SELF']) == "\\") {
        return $url . $_SERVER['HTTP_HOST'];
    } else {
        return $url . $_SERVER['HTTP_HOST'] . dirname($_SERVER['PHP_SELF']);
    }

}

Upvotes: 0

Tim
Tim

Reputation: 901

I've found a solution here: https://stackoverflow.com/a/1240574/7295693

This is the code I'll now be useing:

function get_current_file_url($Protocol='http://') {
   return $Protocol.$_SERVER['HTTP_HOST'].str_replace($_SERVER['DOCUMENT_ROOT'], '', realpath(__DIR__)); 
}

Upvotes: 6

Andy
Andy

Reputation: 5404

Use echo $_SERVER['PHP_SELF'];

For example if the URL is http://localhost/~andy/test.php

The output would be:

/~andy/test.php

That's enough to generate a relative URL.

If you want the directory your current script is running in - without the filename - use:

echo dirname($_SERVER['PHP_SELF']);

In the case above that will give you /~andy (without test.php at the end). See http://php.net/manual/en/function.dirname.php

Please note that echo getcwd(); is not what you want, based on your question. That gives you the location on the filesystem/server (not the URL) that your script is running from. The directory the script is located in on the servers filesystem, and the URL, are 2 completely different things.

There is also a function to parse URL's built in to PHP: http://php.net/manual/en/function.parse-url.php

Upvotes: 11

War10ck
War10ck

Reputation: 12508

Based on your question, I believe this will get you what your want:

$_SERVER['HTTP_HOST'] . substr($_SERVER['REQUEST_URI'], 0, strrpos($_SERVER['REQUEST_URI'], "/"));

Reference:

  • $_SERVER['HTTP_HOST'] - In your case this would return: http://localhost:8888
  • $_SERVER['REQUEST_URI'] - In your case this would return: /dir1/dir2/dir3/myfile.php

With the added substr() and strrpos() methods, you can strip the _myfile.php` off of the end to get the desired result:

http://localhost:8888/dir1/dir2/dir3

Upvotes: 1

adamoffat
adamoffat

Reputation: 649

If your URL is like this: https://localhost.com/this/is/a/url

$_SERVER['DOCUMENT_ROOT'] - gives system path [/var/www/html/this/is/a/url]

$_SERVER['PHP_SELF'] - gives the route of the current file (after the domain name) [/this/is/a/url]

$_SERVER['SERVER_NAME'] - gives the domain name [localhost.com]

$_SERVER['HTTP_REFERER'] - gives the correct HTTP(S) protocol and domain name. [https://localhost.com]

If you would like to get the full url, you can do something like:

echo $_SERVER['HTTP_REFERER'] . $_SERVER['PHP_SELF'];

However, I do believe in this case, that all you need is the relative path.. and in that case you should only need to use $_SERVER['PHP_SELF'];

Upvotes: 6

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