CODEWITHSUNDEEP
djangodjango-views
A I
A I

Reputation: 381

Django links to other other apps

Maybe this question has been answered before in one way or another. But I need to ask because I tried to answer it myself I googled it for days but I couldn't figure it out.

I have an app called reception in my Django project.

I figured out everything but this.

I have the link in the html directing to the right urlpattern. 

 <p><tab1><a href="{% url 'go_to_reception' %}">Reception</a></tab1></p>


urlpatterns = [...,  path('go_to_reception', views.reception, name='go_to_reception'), ...]

And the view is like this

def reception(request):
    return render(request, 'reception.html')

now instead of reception.html I want the link to go the reception page. The app page. What do I need to write there. I have tried everything that came to my mind but nothing worked.

the reception is as follows:

http://127.0.0.1:8000/admin/reception/

So how do I point to this.

Please help! Thanks

Upvotes: 0

Views: 176

Answers (4)

Matthew Manning
Matthew Manning

Reputation: 71

So im just going to write the solution that we discussed in the chat:

{% url "admin:app_list" app_label="reception" %}

documentation

Upvotes: 1

Matthew Manning
Matthew Manning

Reputation: 71

have you got a view called go_to_rececption in your reception.views or a url named go_to_reception in your reception.urls?.

and no worries just trying to help!!!

Upvotes: 0

A I
A I

Reputation: 381

Thank you for your answer Matthew,

After your latest comment, I have changed my code to the following:

<p><tab1><a href="{% url 'reception:go_to_reception' %}">Reception</a></tab1></p>

and in url.py its:

path('reception/', include('reception.urls', namespace='reception-urls')),

in reception.urls.py

app_name = "reception"

and the message now says:

django.urls.exceptions.NoReverseMatch: Reverse for 'go_to_reception' not found. 'go_to_reception' is not a valid view function or pattern name.

I am sorry for going back and forth like this, but I honestly can't make it work.

Upvotes: 0

Matt
Matt

Reputation: 16

Look, this help you? i solve a similar problem in this way

url.py

path('gotoreception', views.reception, name="go_to_reception"),

html

<a href="{% url 'go_to_reception' slug=slug %}"

model

slug = models.SlugField(max_length=255, unique=True)

view

def home(request, slug):
context = {'yourdata':yourdata}
    return render(request,'index.html', context)

On the template tag url you need use the name of your path, you can use a slug if you store the field on your db

3º option but not recommended, you can add the value if you have on a variable but is not a good practice

I recommend you this 2 resources:

  1. https://docs.djangoproject.com/en/2.1/ref/utils/

  2. https://docs.djangoproject.com/en/2.1/ref/templates/builtins/

hardcoded way

can you test this? urls

urlpatterns = [...,  path('reception/', views.reception, name='go_to_reception'), ...]

html

and on the link <a href="127.0.0.1/reception/">

is the hardcoded way but in the future you can have troubles or relative urls, 404 on internal pages

Upvotes: 0

Related Questions