CODEWITHSUNDEEP
xmlxslt
cc0
cc0

Reputation: 1950

Simple find and replace xml header using xsl

I have an xml file with this header;

<?xml version='1.0' encoding='windows-1252'?>

I want to replace the encoding value so it looks like this;

<?xml version='1.0' encoding='utf-16'?>

Any suggestions on how to accomplish this using xsl version 1?

Upvotes: 0

Views: 1059

Answers (1)

Flynn1179
Flynn1179

Reputation: 12075

Have a look at the <xsl:output encoding='utf-16' /> tag.

http://www.w3schools.com/xsl/el_output.asp

As far as managing how it's input, that's up to the XML parser. The identity template with the extra <xsl:output element should be all you need.

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output encoding="utf-16"/>

    <xsl:template match="@* | node()">
        <xsl:copy>
            <xsl:apply-templates select="@* | node()"/>
        </xsl:copy>
    </xsl:template>
</xsl:stylesheet>

Upvotes: 1

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