CODEWITHSUNDEEP
javascriptjquerymouseover
Rollin
Rollin

Reputation: 131

Mouseover Change Image Color

I have a big grid of images. When a user mouseovers an image I want the image to tint blue 0000FF. Is there a way to do this in JS or jquery? Ideally, I wouldn't have to apply a class to each image. This treatment should affect all images on the screen.

After searching the forums here and elsewhere I learned that some folks use a div over the image that has a color and opacity, but how would I apply that to all img?

Another thing I keep seeing is paintbrushJS and pixastic but I don't know how to make those work for this purpose.

Here's the page I'm working on: http://www.rollinleonard.com/elements/

EDIT: the images need to be be clickable so the div can't obstruct the linked img. Is there a way to click through the div or put the div below or something? Some solutions offered don't use a div but I can't figure them out.

Thanks! Rollin

Upvotes: 2

Views: 10670

Answers (4)

Nicholas TJ
Nicholas TJ

Reputation: 1659

This jquery plugin should do the thing you asked pretty well. (tancolor.js)

$("#myImageID").tancolor({mode: "blue"});

There's an interactive demo. You can play around with it.

Check out the documentation on the usage, it is pretty simple. docs

Upvotes: 0

roryf
roryf

Reputation: 30160

Append a span inside each anchor, and adjust it's opacity on hover:

<script>
$(function() {
    $('a').each(function() {
        $(this).appendChild('<span class="overlay" />');
    });
});
</script>

<style>    
    a {
        position: relative;
    }

    a .overlay {
        background-color: #00f;
        height: 100%;
        left: 0px;
        opacity: 0;
        position: absolute;
        top: 0px;
        width: 100%;
    }

    a:hover .overlay {
        opacity: 0.4; /* adjust to suit */
    }
</style>

Note: you'll need to adjust your styles so the anchors are being floated rather than the images.

If you wanted a fade in/out, you could either use CSS3 transitions or hide the span initially and use a jQuery mouseover event to fade it in:

$('a').each(function() {
    $(this).appendChild($('<span class="overlay" />').hide()).hover(function() {
        $(this).find('.overlay').fadeIn(500);
    }, function() {
        $(this).find('.overlay').fadeOut(1000);
    });
});

Upvotes: 1

McHerbie
McHerbie

Reputation: 2995

This is how you're gonna want to do it: http://jsfiddle.net/ztKJB/1/

Javascript / jQuery:

$overlay = $('#overlay');

$('img').bind('mouseenter', function () {
    $this = $(this);
    if ($this.not('.over')) {
        $this.addClass('over');
        $overlay.css({
            width  : $this.css('width'),
            height : $this.css('height'), 
            top    : $this.offset().top + 'px',
            left   : $this.offset().left + 'px',
        }).show();
    }
}).bind('mouseout', function () {
    $(this).removeClass('over');
});

CSS:

#overlay {
    display: block;
    position: absolute;
    background-color: rgba(0, 0, 255, 0.5);
    top: 0px;
    left: 0px;
    width: 0px;
    height: 0px;
}

HTML:

<div id="overlay"></div>
<img src="http://www.rollinleonard.com/elements/zzzthumbs/JPEG/rgb-dots-olan3.jpg" width="150" height="150">
<img src="http://www.rollinleonard.com/elements/zzzthumbs/JPEG/rgb-dots-olan2.jpg" width="150" height="150">
<img src="http://www.rollinleonard.com/elements/zzzthumbs/JPEG/IMG_3291.jpg" width="225" height="150">
<img src="http://www.rollinleonard.com/elements/zzzthumbs/JPEG/1153-1188.jpg" width="200" height="150">
<img src="http://www.rollinleonard.com/elements/zzzthumbs/JPEG/P1010036.jpg" width="200" height="150">
<img src="http://www.rollinleonard.com/elements/zzzthumbs/JPEG/dressRehearsal.jpg" width="267" height="150">
<img src="http://www.rollinleonard.com/elements/zzzthumbs/JPEG/sinWave.jpg" width="225" height="150"
<img src="http://www.rollinleonard.com/elements/zzzthumbs/JPEG/mockUp2.jpg" width="225" height="150">
<img src="http://www.rollinleonard.com/elements/zzzthumbs/JPEG/PICT0453.jpg" width="113" height="150">

Upvotes: 5

mellamokb
mellamokb

Reputation: 56769

The idea of using a div over the image would work. You can generate the div on-the-fly as needed (or generate a hidden div to reuse throughout the page), and position it over the image during the onmouseover event:

$('img').mouseover(function() {
    // generate a div
    // position over current image
});

Upvotes: 1

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