Reputation: 3484
I found this code for filling a range table (source is already offline):
DATA lr_vkorg TYPE RANGE OF vkorg.
TYPES: lr_range_t TYPE RANGE OF vkorg.
lr_vkorg = VALUE lr_range_t(
LET s = 'I'
o = 'EQ'
IN sign = s
option = o
( low = '1100' )
( low = '1200' )
( low = '1300' )
( low = '1400' )
( low = '1500' )
).
But instead of doing something like this:
( low = '1' )
( low = '2' )
...
I want to fill it with the values of an internal table ['1', '2', ...]
.
Does anyone have an idea how to do this?
Update: This is how I did it based on the answer:
DATA:
lt_itab TYPE TABLE OF string,
lt_range_itab TYPE RANGE OF string
.
APPEND '1' TO lt_itab.
APPEND '2' TO lt_itab.
APPEND '3' TO lt_itab.
APPEND '4' TO lt_itab.
lt_range_itab = VALUE #(
FOR <ls_itab> IN lt_itab
( sign = 'I'
option = 'EQ'
low = <ls_itab> )
).
Upvotes: 3
Views: 64543
Reputation: 31
lr_vkorg = VALUE # ( sign = 'I' option = 'EQ' ( low = '1100' ) ( low = '1200' )
( low = '1300' ) ( low = '1400' ) ( low = '1500' ) ).
Upvotes: 3
Reputation: 10621
You can declare macro utilizing your declared structures like this:
DEFINE range.
lr_vkorg = VALUE lr_range_t( BASE lr_vkorg ( sign = 'I' option = 'EQ' low = &1 ) ).
END-OF-DEFINITION.
And then fill your ranges with this one-liner:
range: '1100', '1200', '1300', '1400', '1500', '1600'.
If we speak about filling range from itab, use this statement:
lr_vkorg = VALUE #( FOR ls_vkorg IN gt_vkorg
( sign = 'I'
option = 'EQ'
low = ls_vkorg-vkorg )
).
Upvotes: 5