CODEWITHSUNDEEP
bashshell
Fanni Rákosi
Fanni Rákosi

Reputation: 31

Bash basename only gives back the last name in folder list

FOLDERS=$( basename "$(find "${LOG_DIR}" ! -path "${LOG_DIR}" -type d )")

/storage/archive/fakeagent/2018-07-12
/storage/archive/fakeagent/2018-06-22

With the find command I get this list of folders, and I would like to get the last foldername (dates). When I use basename, I only get back one folder name, the last one: 2018-08-16.

How should I get all of the foldernames?

2018-07-12
2018-07-14
...
2018-08-16

Upvotes: 2

Views: 81

Answers (3)

Mike Q
Mike Q

Reputation: 7337

You should not use the command like this in my opinion. You are mixing folders from different locations into one list, it's largely pointless. In other words, retain the full path in your results if it is going to be of any value. Another thing, you may want to put the values in an array so I will provide an alternative to the answers above :

array=()
while IFS=  read -r -d $'\0'; do
    array+=("$(echo $REPLY | sed 's:.*/::')")
done < <(find . -type d -print0)
echo ${array[@]}

Upvotes: 0

Benjamin W.
Benjamin W.

Reputation: 52431

You could use awk to print whatever is after the last slash of each line:

find "${LOG_DIR}" ! -path "${LOG_DIR}" -type d | awk -F'/' '{print $NF}'

Or you can tell find to print just the basename directly:

find "${LOG_DIR}" ! -path "${LOG_DIR}" -type d -printf '%f\n'

As a side note, uppercase variable names are discouraged as they're more likely to clash with environment and shell variables, see the POSIX spec here, fourth paragraph.

Upvotes: 4

oliv
oliv

Reputation: 13259

You need to use option -a in the basename command to allow multiple arguments:

basename -a $(find "${LOG_DIR}" ! -path "${LOG_DIR}" -type d )

basename --help shows:

-a, --multiple support multiple arguments and treat each as a NAME

If some of your folder have spaces (or control character), you'd better use option -exec in the find command:

find "$LOG_DIR" -type d -exec basename "{}" \;

Upvotes: 4

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