CODEWITHSUNDEEP
python
Crippin
Crippin

Reputation: 165

How to get the method name of a decorated property method?

Lets say I have a method which I decorate with @property.

Is there a way to get the underlying name of the decorated method?

How could I for instance print the name of the property when it does not have a __name__ attribute?

I'm trying to do a RPC call and everything works for methods and static functions but not this.

Upvotes: 1

Views: 322

Answers (3)

Laurent LAPORTE
Laurent LAPORTE

Reputation: 22992

A property has the following attributes: fget, fset and fdel, which are references to the getter/setter/deleter functions.

So, you can get the __name__ of each of this functions (if not None)

Demo:

class Thing(object):
    @property
    def foo(self):
        return "foo"

    def get_baz(self):
        return "baz"

    bar = property(get_baz)

>>> Thing.foo.fget.__name__
'foo'
>>> Thing.bar.fget.__name__
'get_baz'

Upvotes: 3

martineau
martineau

Reputation: 123501

If you use functools.wraps() in your decorator, the decorated function will have the __name__ of the wrapped function.

IF you had some sample code for the decorator in your question, I could show more precisely how to do this...

Upvotes: -1

Komang Suryadana
Komang Suryadana

Reputation: 696

i think if use decorator @property you can access your function with name of function and you can give return value.

class Foo:
   value = 'Foo'
   def setName(self, name):
      self.value = name
   @property
   def name(self):
     return "You name is: {}".format(self.value)

foo = Foo()
print(foo.name)
foo.setName('Bar')
print(foo.name)

Upvotes: -1

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