CODEWITHSUNDEEP
pythonregex
Duck_dragon
Duck_dragon

Reputation: 450

Python regex to check if a string has particular set of numbers

I want to check if this set of number appears in a string in an exact pattern or not:

String I want to check: \4&2096297&0

My code

a = "SCSI\DISK&VEN_MICRON&PROD_1100\4&2096297&0&000200"
print(bool(re.match(r"\4&2096297&0+", a)))

It returns False instead of true. If I try same thing on print(bool(re.match(r"hello[0-9]+", 'hello1'))). I get true. Where am I going wrong?

Upvotes: 0

Views: 102

Answers (2)

Somesh
Somesh

Reputation: 72

    import re

    pattern = "\4&2096297&0"
    print(bool(re.search(pattern,a)))   # this would print "True"

Upvotes: 1

blhsing
blhsing

Reputation: 106975

\4 refers to a character whose ordinal number is octal 4 rather than a literal backslash followed by a 4. You should use a raw string literal for the variable a instead:

a = r"SCSI\DISK&VEN_MICRON&PROD_1100\4&2096297&0&000200"

Also, instead of using r"\4&2096297&0+" as your regex, you should use double backslashes to denote a literal backslash so that \4 would not be interpreted as a backreference:

r"\\4&2096297&0+"

And finally, instead of re.match, you should use re.search since re.match matches the regex from the beginning of the string, which is not what you want.

So:

 import re
 a = r"SCSI\DISK&VEN_MICRON&PROD_1100\4&2096297&0&000200"
 print(bool(re.search(r"\\4&2096297&0+", a)))

would output: True

Upvotes: 0

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