CODEWITHSUNDEEP
javaresourcesclasspathclassloadergetresource
MRalwasser
MRalwasser

Reputation: 15973

How to use ClassLoader.getResources() correctly?

How can I use ClassLoader.getResources() to find recursivly resources from my classpath?

E.g.

And as a bonus question: How does ClassLoader.getResources() differ from ClassLoader.getResource()?

Upvotes: 96

Views: 239240

Answers (5)

Mark Butler
Mark Butler

Reputation: 4391

Here is code based on bestsss' answer:

    Enumeration<URL> en = getClass().getClassLoader().getResources(
            "META-INF");
    List<String> profiles = new ArrayList<>();
    while (en.hasMoreElements()) {
        URL url = en.nextElement();
        JarURLConnection urlcon = (JarURLConnection) (url.openConnection());
        try (JarFile jar = urlcon.getJarFile();) {
            Enumeration<JarEntry> entries = jar.entries();
            while (entries.hasMoreElements()) {
                String entry = entries.nextElement().getName();
                System.out.println(entry);
            }
        }
    }

Upvotes: 13

rec
rec

Reputation: 10905

The Spring Framework has a class which allows to recursively search through the classpath:

PathMatchingResourcePatternResolver resolver = new PathMatchingResourcePatternResolver();
resolver.getResources("classpath*:some/package/name/**/*.xml");

Upvotes: 45

Tomas Narros
Tomas Narros

Reputation: 13488

This is the simplest wat to get the File object to which a certain URL object is pointing at:

File file=new File(url.toURI());

Now, for your concrete questions:

  • finding all resources in the META-INF "directory":

You can indeed get the File object pointing to this URL

Enumeration<URL> en=getClass().getClassLoader().getResources("META-INF");
if (en.hasMoreElements()) {
    URL metaInf=en.nextElement();
    File fileMetaInf=new File(metaInf.toURI());

    File[] files=fileMetaInf.listFiles();
    //or 
    String[] filenames=fileMetaInf.list();
}
  • all resources named bla.xml (recursivly)

In this case, you'll have to do some custom code. Here is a dummy example:

final List<File> foundFiles=new ArrayList<File>();

FileFilter customFilter=new FileFilter() {
    @Override
    public boolean accept(File pathname) {

        if(pathname.isDirectory()) {
            pathname.listFiles(this);
        }
        if(pathname.getName().endsWith("bla.xml")) {
            foundFiles.add(pathname);
            return true;
        }
        return false;
    }

};      
//rootFolder here represents a File Object pointing the root forlder of your search 
rootFolder.listFiles(customFilter);

When the code is run, you'll get all the found ocurrences at the foundFiles List.

Upvotes: 23

krock
krock

Reputation: 29629

There is no way to recursively search through the classpath. You need to know the Full pathname of a resource to be able to retrieve it in this way. The resource may be in a directory in the file system or in a jar file so it is not as simple as performing a directory listing of "the classpath". You will need to provide the full path of the resource e.g. '/com/mypath/bla.xml'.

For your second question, getResource will return the first resource that matches the given resource name. The order that the class path is searched is given in the javadoc for getResource.

Upvotes: 25

bestsss
bestsss

Reputation: 12066

MRalwasser, I'd give you a hint, cast the URL.getConnection() to JarURLConnection. Then use JarURLConnection.getJarFile() and voila! You have the JarFile and you are free to access the resources inside.

The rest I leave to you.

Hope this helps!

Upvotes: 5

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