CODEWITHSUNDEEP
javascriptnode.jsyoutube-data-api
discodane
discodane

Reputation: 2095

How to get video url with youtube api(v3)

I'm working in node on a server and I'm trying to use the YouTube Api to get a video url. The particular url isn't important, this is more of just an exercise. As far as I can tell with the docs, the best way to find a particular video is if it is associated with a channel or user. IE,

  1. query the api with a username(GoogleDevelopers for example)
  2. get it's channel id
  3. query again to get that channels playlists
  4. search a particular playlist to get a playlist item
  5. given a playlistid, search with that to get items(each should represent a video)
  6. item ids have a videoId field, search with that
  7. get video info, but no url?

However, when I get to that point I feel like there should be a url to that video. The though process would be to send this url back to a front end to allow it to use some library to render the video.

QUESTION: Is there a better way to do this? If not, where am I missing the video URL,

Upvotes: 14

Views: 17151

Answers (2)

DMcCallum83
DMcCallum83

Reputation: 550

In your return you should get a videoId:

"id": 
{
  "kind": "youtube#video",
  "videoId": "BsLvIF5c7NU"
}

edit: the return is actually just the id:

"id": "BsLvIF5c7NU"

All you need to do is just append that to the standard url no?:

var url = `https://www.youtube.com/watch?v=${result.id.videoId}`;

Does that make sense?

edit: You could also use part=contentDetails in which case the id is under:

result.items.id

Depending on what you use in the part param will change up the layout of what's returned.

Hope that helps you, dude.

Upvotes: 28

rasulfahad
rasulfahad

Reputation: 624

The answer by @dmccallum83 is correct.

If for some reason you can't (don't want to) concatenate strings -

const youtube = require("googleapis").youtube('v3');

async function getVideoUrl(videoId) {
  const res = await youtube.videos.list({
    part: "snippet,contentDetails",
    id: videoId,
  });

  const video = res.data.items[0];

  return video.snippet.resourceId.url;
}

const videoId = "YOUR_VIDEO_ID";

const videoUrl = await getVideoUrl(videoId);

Get the video id from the response of your upload request and use that to get the video details using the videos.list method which will return a list of videos, including the video url.

Upvotes: 1

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