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c#c#-6.0string-interpolation
M.Hassan
M.Hassan

Reputation: 11032

Long string interpolation lines in C#6 don't support Tab,CR and LF

I tried to use string interpolation $"" in C#6 with tabs

 var name="My Name";
 var text =$"\t\t{name}";

and it's working fine and tabs \t is resolved.

When trying to use Long string interpolation lines

      var name = "myname";
      var text = $@"\t\t{name}
                    tab and name  is in a Long string interpolation \r\n
       ";
    Console.WriteLine(text);

output

     \t\tmyname
                    tab and name  is in a Long string interpolation \r\n

The tab \t ,\r and \n aren't resolved

So i had to use string.Format() to resolve this issue.

The question:

Is this a limitation in the Long string interpolation for not supporting \t \r \n in c#6 (even c#7)

Upvotes: 2

Views: 2748

Answers (2)

Rufus L
Rufus L

Reputation: 37030

You have the verbatim modifier @ in front of that string, so your tab characters will be un-escaped and treated as normal text. If you want to include them in the string, then you can either enclose the characters in curley brackets (since you're also using the $ string interpolation modifier) so they're treated as tabs (same with the carriage return and newline characters):

    var name = "myname";
    var text = $@"{"\t\t"}{name}
            tab and name  is in a Long string interpolation {"\r\n"}
";
    Console.WriteLine(text);

Alternatively, since it's a verbatim string, you can just press Tab (or Enter) keys where you want those characters in the string.

This string is the same as the one above:

    var text = $@"      {name}
            tab and name  is in a Long string interpolation 

";

Upvotes: 4

Selman Genç
Selman Genç

Reputation: 101701

You are using verbatim string in your second example so \t is being escaped. It has nothing to do with string interpolation.

If you want to use tab character don't use verbatim string. You can concatenate multiple lines using string concatenation with "+"

Upvotes: 3

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