Reputation: 1248
I'm in a bit of a pickle: I've been asked to take in comments starting with a specific string from a database, and separate the result into separate columns.
For example -- if a returned value is this:
COLUMN_ONE
--------------------
'D7ERROR username'
The return needs to be:
COL_ONE COL_TWO
--------------------
D7ERROR username
Is it even possible to define columns once the result set has been structured just for the sake of splitting a string into two?
Upvotes: 29
Views: 224924
Reputation: 41
Simple way is to convert into column
SELECT COLUMN_VALUE FROM TABLE (SPLIT ('19869,19572,19223,18898,10155,'))
CREATE TYPE split_tbl as TABLE OF VARCHAR2(32767);
CREATE OR REPLACE FUNCTION split (p_list VARCHAR2, p_del VARCHAR2 := ',')
RETURN split_tbl
PIPELINED IS
l_idx PLS_INTEGER;
l_list VARCHAR2 (32767) := p_list;
l_value VARCHAR2 (32767);
BEGIN
LOOP
l_idx := INSTR (l_list, p_del);
IF l_idx > 0 THEN
PIPE ROW (SUBSTR (l_list, 1, l_idx - 1));
l_list := SUBSTR (l_list, l_idx + LENGTH (p_del));
ELSE
PIPE ROW (l_list);
EXIT;
END IF;
END LOOP;
RETURN;
END split;
Upvotes: 4
Reputation: 588
With REGEXP_SUBSTR is as simple as:
SELECT REGEXP_SUBSTR(t.column_one, '[^ ]+', 1, 1) col_one,
REGEXP_SUBSTR(t.column_one, '[^ ]+', 1, 2) col_two
FROM YOUR_TABLE t;
Upvotes: 47
Reputation: 332771
Depends on the consistency of the data - assuming a single space is the separator between what you want to appear in column one vs two:
SELECT SUBSTR(t.column_one, 1, INSTR(t.column_one, ' ')-1) AS col_one,
SUBSTR(t.column_one, INSTR(t.column_one, ' ')+1) AS col_two
FROM YOUR_TABLE t
Oracle 10g+ has regex support, allowing more flexibility depending on the situation you need to solve. It also has a regex substring method...
Reference:
Upvotes: 56