CODEWITHSUNDEEP
crystal-lang
Stepan Vanzuriak
Stepan Vanzuriak

Reputation: 304

Call block with call not work

I try to use code from this issue

def call(&block)
  block.call(3, "test")
end

call do |x, y|
  puts x
  {x, y}
end

But only get error:

wrong number of block arguments (given 2, expected 0)

Is it ok, maybe there is some other way to call block?

Playground link: https://play.crystal-lang.org/#/r/4t8h

Github issue: https://github.com/crystal-lang/crystal/issues/6597

Upvotes: 1

Views: 85

Answers (1)

WPeN2Ic850EU
WPeN2Ic850EU

Reputation: 995

You can use either of these two forms:

def call(&block : Int32, String -> {Int32, String})
  block.call(3, "test")
end

result = call do |x, y|
  {x, y}
end

result # => {3, "test"}

or

def call
  yield 3, "test"
end

result = call do |x, y|
  {x, y}
end

result # => {3, "test"}

And some additional info can be found here.

Upvotes: 1

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