CODEWITHSUNDEEP
pythonpython-3.x
jonikvir
jonikvir

Reputation: 5

TypeError: 'NoneType' object is not callable but object is not nonetype

def winner(board):
    WAYS_TOWIN = ((0, 1, 2),
                  (3, 4, 5),
                  (6, 7, 8),
                  (0, 4, 8),
                  (2, 4, 6),
                  (0, 3, 6),
                  (1, 4, 7),
                  (2, 5, 8))
    for row in WAYS_TOWIN:
        if board[row[0]] == board[row[1]] == board[row[2]] != " ":
            winner = board[row[0]]
            return winner
    if " " not in board:
            return TIE
    else:
        return None



#Main
instructions()
human = input("Enter your name: "); print("\n")
pieces = who_first(human, computer); print("\n")#pieces becomes a list with human piece first and computer piece second
board = new_board(); print("\n")
winner = winner(board)



while winner == None and winner != TIE:
    if turn == pieces[0]:#if human is first
        winner = winner(board)

When I run the winner function the first time, it returns none to the winner variable and there are no errors. But when I run it for the second time it gives me TypeError: 'NoneType' object is not callable. The board is a list with [" "]*9 and i dont get why calling the board the second time is a nonetype object.

Upvotes: 0

Views: 2526

Answers (1)

ikuamike
ikuamike

Reputation: 335

The first time you run winner = winner(board) winner becomes None therefore on the second call it's not calling the function but None hence the Error. Changing the names will solve the problem, it's not recommended to use same variable name and function name.

Upvotes: 1

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