Reputation: 359
I am trying to show the forecast for a city from openweathermap. But my foreach show nothing. Whats wrong?
<?php
$url = "http://api.openweathermap.org/data/2.5/forecast?zip=85080,de&lang=de&APPID=MYKEY";
$contents = file_get_contents($url);
$clima = json_decode($contents, true);
foreach($clima as $data) {
echo $data->list->main->temp_min;
}
?>
Upvotes: 1
Views: 4979
Reputation: 157
Lets try it...
<?php
$city = 'Dhaka';
$country = 'BD';
$url = 'http://api.openweathermap.org/data/2.5/forecast/daily?q=' . $city . ',' . $country . '&units=metric&cnt=7&lang=en&appid=c0c4a4b4047b97ebc5948ac9c48c0559';
$json = file_get_contents( $url );
$data = json_decode( $json, true );
$data['city']['name'];
// var_dump($data );
foreach ( $data['list'] as $day => $value ) {
echo 'Max temperature for day ' . $day
. ' will be ' . $value['temp']['max'] . '<br />';
echo '<img src="http://openweathermap.org/img/w/' . $value['weather'][0]['icon'] . '.png"
class="weather-icon" />';
}
Upvotes: 2
Reputation: 1615
You used json_decode
with parameter associative to true.
So $data is rather an array not an object.
Based on that sample (similar to your url), you should access your values with square bracket syntax :
$data['main']['temp_min'];
Upvotes: 1
Reputation: 3819
The result from a json_decode(string, true)
is an associative array.
<?php
$url = "http://api.openweathermap.org/data/2.5/forecast?zip=85080,de&lang=de&APPID=MYKEY";
$contents = file_get_contents($url);
$clima = json_decode($contents, true);
foreach($clima['list'] as $data) {
echo $data['main']['temp_min'];
}
?>
If you want to use object syntax, don't set associative to true
.
$clima = json_decode($contents);
foreach($clima->list as $data) {
echo $data->main->temp_min;
}
Upvotes: 6