CODEWITHSUNDEEP
pythonseleniumselenium-webdriverwebdrivergetattribute
ben
ben

Reputation: 1122

How to retrieve the value of the attribute aria-label from element found using xpath as per the html using Selenium

I have the following HTML span:

<button class="coreSpriteHeartOpen oF4XW dCJp8">
    <span class="glyphsSpriteHeart__filled__24__red_5 u-__7" aria-label="Unlike"></span>
</button>

I also have a webElement representing the button containing this span that I have found using xpath. How can I retrieve the aria-label value (Unlike) from the element?

I tried to do:

btn = drive.find_element(By.xpath, "xpath") 
btn.get_attribute("aria-label")

but it returns nothing. How to retrieve the text value of an element with 'aria-label' attribute from the element object?

Upvotes: 8

Views: 25472

Answers (5)

sule mohammed
sule mohammed

Reputation: 137

If xpath seems complicated, you can retrieve it with the class name and use the get_attribute method to access it.

value = driver.find_element(By.CLASS_NAME, 'glyphsSpriteHeart__filled__24__red_5 u-__7')
output = value.get_attribute("aria-label")

Upvotes: 0

Vishal Kharde
Vishal Kharde

Reputation: 1737

Following worked for me in Java,

WebElement btnelement= driver.findElement(
                        By.xpath("//span[@aria-label='Unlike']"));
System.out.println("Attribute value is " + btnelement.getAttribute("value"));

Upvotes: 1

Abhijeet Shevate
Abhijeet Shevate

Reputation: 1

# Like method
lov = el.find_element_by_class_name('glyphsSpriteHeart__outline__24__grey_9').click()  

# Unlike method
lov = el.find_element_by_class_name('glyphsSpriteHeart__filled__24__red_5').click()

I used these methods instead and it worked!

Upvotes: 0

Sers
Sers

Reputation: 12255

aria-label is attribute of span element, not button. You can get it like this:

btn = drive.find_element(By.xpath, "xpath") 
aria_label = btn.find_element_by_css_selector('span').get_attribute("aria-label")

Or if your goal is to find button with span contains attribute aria-label="Unlike":

btn = drive.find_element(By.XPATH, '//button[./span[@aria-label="Unlike"]]')
#you can add class to xpath also if you need
btn = drive.find_element(By.XPATH, '//button[./span[@aria-label="Unlike"] and contains(@class,"coreSpriteHeartOpen)]')

Upvotes: 10

undetected Selenium
undetected Selenium

Reputation: 193298

As per your question and the HTML you have shared it seems that the element is a React element, so to retrieve the attribute aria-label you have to induve WebDriverWait for the desired element to be visible and you can use the following solution:

print(WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "element_xpath_you_found"))).get_attribute("aria-label"))

Note : You have to add the following imports :

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

Upvotes: 0

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