CODEWITHSUNDEEP
pythonpython-3.x
CaptainPyPy
CaptainPyPy

Reputation: 58

Can a default parameter be used after being followed by *args?

For example if I have: 

def foo(arg1, def_par="yes", *args,**kwargs):
     print(arg1,def_par)

     for key, value in kwargs.items():
          print("{},{}".format(key,value))

     for arg in args:
         print(arg)

foo("Hello",1,2,smell="funky")

Then the interpreter outputs:

>>Hello 1
>>smell,funky
>>2

Is there a way to create an output where, unless explicitly defined by a keyword argument, the default argument is used to create an output such as: 

>>Hello Yes
>>smell,funky
>>1
>>2

Upvotes: 1

Views: 77

Answers (1)

blhsing
blhsing

Reputation: 106455

You can put variable positional arguments before keyword arguments:

Change:

def foo(arg1, def_par="yes", *args,**kwargs):

to:

def foo(arg1, *args, def_par="yes", **kwargs):

With this change, your code would output:

Hello yes
smell,funky
1
2

If for some reason you can't or don't want to change the function signature of foo, you can obtain the default value of a parameter with inspect.signature:

import inspect
foo("Hello", inspect.signature(foo).parameters['def_par'].default, 1, 2, smell="funky")

Upvotes: 2

Related Questions