CODEWITHSUNDEEP
c
user302593
user302593

Reputation: 121

Question about input with scanf

When I execute the following program it get the user input for account details and then prints it correctly, but it cannot read the opt value (y/n). It automatically calls again. How can I get the program to exit when the user inputs "n"?

    char opt;
    do
{

//Getting user input

printf("\n Enter the Account Number:\n ");
scanf("%d",&gAccNo_i);                                       
printf("\n Enter the Account Holder's Name:\n ");
scanf("%s",gCustName_c);
printf("\n Enter the Balance Amount:\n ");
scanf("%f",&gBlncAmt_f);

//Printing the input data.

printf("\n Account Number     : %d",gAccNo_i);
printf("\n Customer Name      : %s",gCustName_c);
printf("\n Balance Amount     : %f",gBlncAmt_f);

printf("\n Do u want to wish to continue?(y/n)");
scanf("%c",&opt);
}while(opt!='n');

Upvotes: 1

Views: 263

Answers (2)

Javed Akram
Javed Akram

Reputation: 15354

use opt=getch(); inplace of scanf("%c",&opt);

OR

scanf reads the whitespace that is left in the buffer by previous line. To skip whitespace, add a space to the "%c":

scanf(" %c", &opt);

Upvotes: 3

Shamim Hafiz - MSFT
Shamim Hafiz - MSFT

Reputation: 22114

scanf("%c",&opt);

Will actually read in a space/newline character. Which obviously will not be equal to 'n'.

You may like to take the input as a string and then verify if the first character is a 'n'.

char opts[5];
scanf("%s",opts);
while(opts[0] !='n');

Upvotes: 0

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