Reputation: 161
If I want to randomly select a letter between a and z, I assume I have to use the Random
class:
Random rand = new Random();
But since this only generates numbers, what do I need to do to apply this to letters?
Upvotes: 16
Views: 47320
Reputation: 55876
alter version of @Michael Barker
Random r = new Random();
int c = r.nextInt(26) + (byte)'a';
System.out.println((char)c);
Upvotes: 3
Reputation: 21
why assume to use Random instead of Math.random? You can even make the code shorter...
public static char genChar(){
return (char)(Math.random()*26 + 'a');
}
Upvotes: 2
Reputation: 11
To randomly select a letter from (a- z) I would do the following:
Random rand = new Random();
...
char c = rand.nextInt(26) + 'a';
Since Random.nextInt() generates a value from 0 to 25, you need only add an offset of 'a' to produce the lowercase letters.
Upvotes: 1
Reputation: 14550
import static org.apache.commons.lang3.RandomStringUtils.randomAlphabetic;
...
randomAlphabetic(1).toLowerCase()
this gives you a string with single character
Upvotes: 1
Reputation: 1
Random r = new Random();
char symbel = (char)(r.nextInt(26) + 'a');
if(symbel>='a' && symbel <= 'z') {
System.out.println("Small Letter" + symbel);
} else {
System.out.println("Not a letter" + symbel);
}
Upvotes: 0
Reputation: 14398
Random r = new Random();
char c = (char) (r.nextInt(26) + 'a');
Upvotes: 27
Reputation: 54742
use the ascii value of the letters to generate the random number.
Upvotes: 0
Reputation: 2678
Letters, or more exactly, characters, are numbers (from 0 to 255 in extended ascii, 0 to 127 in non-extended). For instance, in ASCII, 'A' (quote means character, as opposed to string) is 65. So 1 + 'A' would give you 66 - 'B'. So, you can take a random number from 0 to 26, add it to the character 'a', and here you are : random letter.
You could also do it with a string, typing "abcdefghijklmnopqrstuvwxyz" and taking a random position in this chain, but Barker solution is more elegant.
Upvotes: 5