CODEWITHSUNDEEP
regexlinuxbashfind
Judy
Judy

Reputation: 1871

Capture log files that ended with any number

We want to capture all logs that ended with ".log.[any number]

So I create this syntax

find .  -type f  -regex '\.log\.*[0-9]$' -print

command does not give any output

But this doesn't capture the files as the following ( expected results )

  controller.log.2018-01-03-01  
  server.log.2017-10-31-03
  server.log.2018-01-23-11
  server.log.2018-04-06-17  
  server.log.2018-07-07-05
  controller.log.2018-01-03-02  
  log-cleaner.log.10           
  server.log.2017-10-31-04 
  server.log.2018-01-23-12  
  server.log.2018-04-06-18 
  server.log.2018-07-07-06
  controller.log.2018-01-03-03 
  log-cleaner.log.2   
  server.log.232.434

what is wrong with my syntax ?

Upvotes: 0

Views: 184

Answers (2)

Joaquin
Joaquin

Reputation: 2091

From find manpage:

-regex pattern

File name matches regular expression pattern. This is a match on the whole path, not a search. For example, to match a file named ./fubar3, you can use the regular expression .*bar. or .*b.*3, but not f.*r3. The regular expressions understood by find are by default Emacs Regular Expressions, but this can be changed with the -regextype option.

So, you must match the whole path, in this case you could try with:

find .  -type f  -regex '.*\.log.*[0-9]$' -print

Upvotes: 1

RavinderSingh13
RavinderSingh13

Reputation: 133458

Could you please try following.(considering that your files are same format as shown samples)

find . -regextype posix-extended -regex ".*\.log.[0-9]{4}(-[0-9]{2}){3}"

Upvotes: 0

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