Reputation: 67
Date date = new Date();
try {
date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS").parse(s);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
Timestamp timestamp=new Timestamp(date.getTime());
id=Long.parseLong(timestamp.toString());
On executing the above code I got this error:
java.lang.NumberFormatException: For input string: "2018-08-29 16:35:31.753"
at
java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
What's wrong in it now?
Upvotes: 0
Views: 961
Reputation: 28279
The error happens when you try to get long value by Timestamp.toString()
, since it returns 2018-08-29 16:35:31.753
, which is not a valid long.
Just use:
long id = timestamp.getTime();
Upvotes: 2