CODEWITHSUNDEEP
pythonmatplotlib
Dimitris Lolis
Dimitris Lolis

Reputation: 13

How to space out the x values with uneven axis in matplotlib?

from matplotlib import pyplot as plt
import numpy as np

x = np.linspace(448312,497812,100)
y = np.linspace(7188379,7986879,1598)
z = np.random.rand(100,1598)
interp_method = "sinc"
fig, axs = plt.subplots()
axs.imshow(z, interpolation=interp_method, cmap='viridis', extent= (x[0], x[-1], y[0], y[-1]))
axs.set_title(str(interp_method))
plt.show()

# the image is on https://imgur.com/ZYIkqAw

The previous code produces a heatmap that isn't quite readable, is there a way to "expand" the x axis without creating interpolated values? I tried several approaches but all failed I changed figsize (failed), i changed the axes with:

axs=plt.axes([.65, .6,  10, 10], facecolor='k',aspect='equal')

but it ultimately is impossible to widen the heatmap enough to make it clearer. I don't really want to create empty values in the x axis and use a plot to interpolate them. Is there a way to "zoom" in to x axis and make the plot seem square?

I checked the following links thoroughly but i couldn't get something that could've helped:

How to change spacing between ticks in matplotlib?

How do I add space between the ticklabels and the axes in matplotlib?

https://matplotlib.org/api/_as_gen/matplotlib.axes.Axes.set_aspect.html

Thanks in advance everyone :) Any help is much appreciated

Upvotes: 1

Views: 755

Answers (1)

Raf
Raf

Reputation: 1767

If you want a square plot:

axs.imshow(z, interpolation=interp_method, cmap='viridis', extent= (x[0], x[-1], y[0], y[-1]), aspect=“auto”)

Note it is the same code as yours, just added the aspect=“auto” argument to imshow().

Here's the image: https://i.sstatic.net/U2GFD.jpg

Upvotes: 1

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