CODEWITHSUNDEEP
bashshellunix
Deepak
Deepak

Reputation: 27

while using grep with find getting error like "grep: illegal option "

I am trying to read records from file and if string is available in any files then print that file. code:

while read line
do
find ./q/q*.q -type f -exec grep -ls $line {} +
donr< "file_name"

file_name have data like:

india
usa_k
in_va

while execution i am getting grep: illegal option error

Same time I want to store o/p of find in variable. Any help

in loop only i want to concate $line and find o/p and direct in txt file.

code some like:

$line | o/p find >> missing.txt

In i/p file if we have value "INDIA" if this value is aviable in other txt file then i want to print "india is aviable in (filename)" and store this information in txt file. this we need to do for all values..

Upvotes: 1

Views: 1703

Answers (1)

Charles Duffy
Charles Duffy

Reputation: 295716

Put -- before your names as an end-of-option terminator, -e before the expansion of "$line", and quote that expansion. This prevents either the names or the search string from being read as options.

while IFS= read -r line; do
  find ./q/q*.q -type f -exec grep -l -e "$line" -- {} + |
    while IFS= read -r matched_file; do
      echo "$line is available in $matched_file"
    done
done <file_name >results.txt

Upvotes: 1

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