San Diego
San Diego

Reputation: 81

Python text replace with for loop

I am just trying to remove all datetime values... but everytime it is going to the beginning and refreshing the text with the last value. How can i delete the all time values ?

My text file is hey.txt and this is the inside of it:

14:15
24:32
trying
42:56
1:42
for
testing

Code part:

import re
filename = "hey.txt"
text = open(filename).read()
n,i,c,x,=(0,0,0,0)
datetimes = []
for number in range(3600):
    n+=1
    b=str(n)
    if n<10:
        b = "0"+str(n)
    elif n==60:
        i+=1
        n=0 
    datetimes.append("%d:%s"%(i,b)) 
for word in datetimes:    
    matches = re.compile(word).finditer(text)
    for match in matches:
        z= match.group(0)
        print(z)
        if z==word:
            open("datetimes-doc.txt","w+").write(text.replace(z,""))
            c+=1
        elif z!=word:
            c+=1
        print("proccess:%d"%c)

and this is the my sending file datetimes-doc.txt

14:15
24:32
trying

1:42
for
testing

here is the some of output from console:

1:42
proccess:1
2:56
proccess:2
4:15
proccess:3
4:32
proccess:4
14:15
proccess:5
24:32
proccess:6
42:56
proccess:7

Upvotes: 1

Views: 1103

Answers (1)

VanTan
VanTan

Reputation: 657

Rather than a for loop, why not:

#read entire file's content 
with open('hey.txt') as f:
    content = f.read()

# find time and replace with empty string
new_content = re.sub(r'[0-5]*[0-9]:[0-5]*[0-9]\n','', content)

#write results into file
with open('hey2.txt', 'w') as f:
    f.write(new_content)

Upvotes: 2

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