CODEWITHSUNDEEP
pythonregexstring
user32882
user32882

Reputation: 5885

not matching a set number of characters in regex

I have the following expression

diff_pr_EUR-44_cordex_rcp45_mon_ave_2048-2060_minus_2005-2017_mon10_ave1_withsd.nc

I would like to use regex to extract and generate the following string

rcp45_mon10

I have tried this so far with the online regex tester

rcp\d\d[^.]+mon\d+

Which extracts more than what I need...

rcp45_mon_ave_2048-2060_minus_2005-2017_mon10

How can I get regex to skip subsequent characters until it reaches the mon10 part?

Thanks

Upvotes: 3

Views: 40

Answers (2)

anubhava
anubhava

Reputation: 785481

You may use re.sub here:

>>> s = 'diff_pr_EUR-44_cordex_rcp45_mon_ave_2048-2060_minus_2005-2017_mon10_ave1_withsd.nc'
>>> print (re.sub(r'^.*?(rcp\d+).*(_mon\d+).*', r'\1\2', s))
rcp45_mon10

RegEx Demo

Details:

  • ^.*?: Match 0 or of any characters at the start (lazy)

  • (rcp\d+): Match and capture rcp followed by 1+ digits in group #1

  • .*: Match 0 or of any characters (greedy)

  • (_mon\d+): Match and capture _mon followed by 1+ digits in group #2

  • .*: Match anything till the end

  • r'\1\2': Replace string by back-references of group #1 and group #2

Upvotes: 2

user3483203
user3483203

Reputation: 51165

You can match using two matching groups, and join:

>>> ''.join(re.findall(r'(rcp\d{2}).*?(\_mon\d{2})', s)[0])
'rcp45_mon10'

Upvotes: 2

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