CODEWITHSUNDEEP
javafirebasefirebase-realtime-databasefirebase-admin
MaterialZ
MaterialZ

Reputation: 351

remove a value from firebase database

I'm trying to delete a node from Firebase database but nothing happens.

This is my code:

FileInputStream serviceAccount = new FileInputStream(keyPath);

FirebaseOptions options = new FirebaseOptions.Builder()
    .setCredentials(GoogleCredentials.fromStream(serviceAccount))
    .setDatabaseUrl(databaseUrl)
    .build();

FirebaseApp.initializeApp(options);

DatabaseReference ref = FirebaseDatabase.getInstance().getReference();
ref.child("Users").child(uid).child("name").removeValue()

This is the output:

SLF4J: Failed to load class "org.slf4j.impl.StaticLoggerBinder".
SLF4J: Defaulting to no-operation (NOP) logger implementation
SLF4J:See http://www.slf4j.org/codes.html#StaticLoggerBinder for further details.

09-02-2018 05:43:53 PM - [START] - Start action : Statement - serviceAccount = new java.io.FileInputStream(keyPath) 09-02-2018 05:43:53 PM - [END] - End action : Statement - serviceAccount = new java.io.FileInputStream(keyPath) 09-02-2018 05:43:53 PM - [START] - Start action : Statement - options = new com.google.firebase.FirebaseOptions$Builder().setCredentials(com.google.auth.oauth2.GoogleCredentials.fromStream(serviceAccount)).setDatabaseUrl(databaseUrl).build() 09-02-2018 05:43:53 PM - [END] - End action : Statement - options = new com.google.firebase.FirebaseOptions$Builder().setCredentials(com.google.auth.oauth2.GoogleCredentials.fromStream(serviceAccount)).setDatabaseUrl(databaseUrl).build() 09-02-2018 05:43:53 PM - [START] - Start action : Statement - com.google.firebase.FirebaseApp.initializeApp(options) 09-02-2018
05:43:53 PM - [END] - End action : Statement - com.google.firebase.FirebaseApp.initializeApp(options) 09-02-2018
05:43:53 PM - [START] - Start action : Statement - ref = com.google.firebase.database.FirebaseDatabase.getInstance().getReference()
09-02-2018 05:43:53 PM - [END] - End action : Statement - ref = com.google.firebase.database.FirebaseDatabase.getInstance().getReference()
09-02-2018 05:43:53 PM - [START] - Start action : Statement ref.child("Users").child(uid).child("name").removeValue() 09-02-2018
05:43:53 PM - [END] - End action : Statement - ref.child("Users").child(uid).child("name").removeValue() 09-02-2018
05:43:53 PM - [PASSED] - Test Cases/V2/General/Draft 09-02-2018
05:43:53 PM - [END] - End Test Case : Test Cases/V2/General/Draft

As I said, nothing changes on the database.
Any ideas?

Upvotes: 1

Views: 159

Answers (1)

MaterialZ
MaterialZ

Reputation: 351

I eventually found this repository on github: https://github.com/bane73/firebase4j
In the readme file, there is a simple example of writing a value to firebase database by providing only the database url and the data you want to write.
In order to delete a value, just set the value to null:

String url = 'https://project-name.firebaseio.com/users/user1/email'

//Initialize database
Firebase firebase = new Firebase(baseUrl);

//remove email of user1
Map<String, Object> dataMap = new LinkedHashMap<String, Object>();
dataMap.put("some str", null);
firebase.put(dataMap)

Upvotes: 0

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