CODEWITHSUNDEEP
javajsongson
BrunoTS
BrunoTS

Reputation: 171

GSON deserialize json string without all fields

I have a Java object with so so many fields... 

 public class Foo {
        private String field0;
        private String field1;
        private String field2;
        private String field3;
        private String field4;
        private String field5;
        private String field6;
        private String field7;
        private String field8;
        private String field9;

        // Getters and Setters...

    }

And I have the following JSONString...

{\"field0\": \"value0\", \"field1\": \"value1\"}

I instantiate Gson with GsonBuilder() as follows...

        gson = new GsonBuilder()//
                .disableHtmlEscaping()//
                .setFieldNamingPolicy(FieldNamingPolicy.UPPER_CAMEL_CASE) //
                .setPrettyPrinting()//
                .serializeNulls()//
                .setDateFormat("yyyy/MM/dd HH:mm:ss [Z]")//
                .create();

And when i call gson.fromJson(JSONString, Foo.class); I got a new instance of Foo with all fields set as null. Even field0 and field1 that was specified in my JsonString...

How can I deserialize the JSONString above to get an instance with field0 and field1 set?

Upvotes: 0

Views: 382

Answers (1)

Andrew Jenkins
Andrew Jenkins

Reputation: 1609

You set FieldNamingPolicy.UPPER_CAMEL_CASE, change the JSON string to {\"Field0\": \"value0\", \"Field1\": \"value1\"}.

Upvotes: 1

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