CODEWITHSUNDEEP
javascriptarraysobject
Michael
Michael

Reputation: 576

JavaScript remove keys of object and keep same order

I have an object or array (i am not sure) that looks like this:

0:{62: "01:30:00 - 01:45:00"}
1:{61: "01:30:00 - 01:45:00"}
2:{55: "03:15:00 - 04:15:00"}
...

My goal is to make it look like this:

62:"01:30:00 - 01:45:00"
61:"01:30:00 - 01:45:00"
...

I need to keep the same order as in the first object this is very important. I've tried this but the result is the exact same.

finalOptions = [];
for (var newKey in newOptions) {
    finalOptions.push(newOptions[newKey]);
}

console.log(finalOptions);

Upvotes: 1

Views: 2401

Answers (6)

Trevor
Trevor

Reputation: 31

It's best to iterate over objects if they are arrays so first you can do

   const myObject =  {
     0:{62: "01:30:00 - 01:45:00"},
     1:{61: "01:30:00 - 01:45:00"},
     2:{55: "03:15:00 - 04:15:00"}
   };

   const objToArray = Object.values(myObject);  //makes the array
   const objYouWant = {}; //Initializes place to build your object

  //iterates over array you just made translating each index into a key-value pair
   const backToObject = objToArray.map((item => {
    return objYouWant[item.key] = item.value
   })

If you console.log objYouWant you should get 

   {
     62: ""01:30:00 - 01:45:00",
     61: "01:30:00 - 01:45:00",
     55: "03:15:00 - 04:15:00"
   }

Which is I think, what you want

Upvotes: 0

michaelitoh
michaelitoh

Reputation: 2340

If you have an Array of object you can try:

var ar = [{0: {62: "01:30:00 - 01:45:00"}, 1: {61: "01:30:00 - 01:45:00"},2: { 55: "03:15:00 - 04:15:00" }}]
 
var result;
for (el of ar) {
  for (obj in el) {
    for (text in el[obj]) {
      result = el[obj][text];result 
      console.log(result)
    }
  }
}

But if you have An object, you can try this:

var obj = {
              0: { 62: "01:30:00 - 01:45:00" },
              1: { 61: "01:30:00 - 01:45:00" },
              2: { 55: "03:15:00 - 04:15:00" }
          };
var result;
for (key in obj) {
  for (el in obj[key]) {
    result = obj[key][el];
    console.log(result)
  }
}

Upvotes: 0

Artem Arkhipov
Artem Arkhipov

Reputation: 7455

if you want to keep the order and know both key and a value, you can run this code to get an array of objects where key and value are specified and order is the same.

const initial = [
        {62: "01:30:00 - 01:45:00"},
        {61: "01:30:00 - 01:45:00"},
        {55: "03:15:00 - 04:15:00"}];

    const finalOptions = [];
    for (let i=0; i<initial.length; i++) {
        let option = initial[i];
        let key = Object.keys(option)[0]; // get first and only key from option
        finalOptions.push({key:key, value: option[key]});
    }
    
    console.log(finalOptions);

Upvotes: 0

lviggiani
lviggiani

Reputation: 6066

Try this:

var myObject = {
  0:{62: "01:30:00 - 01:45:00"},
  1:{61: "01:30:00 - 01:45:00"},
  2:{55: "03:15:00 - 04:15:00"}
};

var newObject = {};
for (s in myObject) {
  for (ss in myObject[s])
    newObject[ss] = myObject[s][ss];
}

console.log(newObject);

This if you want to keep the orignal order

var myObject = {
  0:{62: "01:30:00 - 01:45:00"},
  1:{61: "01:30:00 - 01:45:00"},
  2:{55: "03:15:00 - 04:15:00"}
};

var newObject = [];
for (s in myObject) {
  for (ss in myObject[s])
    newObject.push(myObject[s][ss]);
}

console.log(newObject);

Upvotes: 1

Mohammad Usman
Mohammad Usman

Reputation: 39332

In case you are working with an array of objects, you can use .reduce() method:

let data = [
  {62: "01:30:00 - 01:45:00"},
  {61: "01:30:00 - 01:45:00"},
  {55: "03:15:00 - 04:15:00"}
];

let result = data.reduce((a, c) => {
  let [[k, v]] = Object.entries(c);
  a[k] = v; return a;
}, {});

console.log(result);

Upvotes: 0

Jacob Nelson
Jacob Nelson

Reputation: 2476

what you have is an array of objects. What you are trying to do is read objects from array1 (newOptions) and assign to array2 (finalOptions). Results will definitely be same.

enter image description here

This is the way Chrome Developer Console will show arrays to understand array index and corresponding values

Upvotes: 0

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