CODEWITHSUNDEEP
pythonwindowsnfs
krakowi
krakowi

Reputation: 613

Open explorer on a network path

Let's say I have a network path like this below:

\\srv\teams\dir 1

How can I open it using subprocess? I am trying:

subprocess.Popen("explorer '\\srv\teams\dir 1'")

but it always leads me to my 'My Documents'. It works fine from cmd. I am using win7.

I also tried:

os.system("explorer '\\srv\teams\dir 1'")

Upvotes: 0

Views: 577

Answers (2)

Hai Vu
Hai Vu

Reputation: 40763

Please see Mike Scotty for solution regarding os.system. If you use subprocess, please use a list of string for your command instead of a single string:

subprocess.call(['explorer', '\\\\srv\\teams\\dir 1'])

Note that I use subprocess.call instead of subprocess.Popen since this is a simple call, no need to overkill

Upvotes: 1

Mike Scotty
Mike Scotty

Reputation: 10782

There are two issues with your code:

1) Use a raw string or escape your \ characters

2) Use " instead of ' to enclose the path

os.system(r'explorer "\\srv\teams\dir 1"')

Upvotes: 1

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