CODEWITHSUNDEEP
pythonregex
E235
E235

Reputation: 13500

How to find all the strings with length 5 and have 1 digit and 4 letters divided to all group combinations

I need regex to count all the groups of strings with length of 5 that contains 1 digit (0-9) and 4 small letters (a-z) with the following:

I know how to match all the strings with length of 5 with letters and 1 digit:
^(?=.{5}$)[a-z]*(?:\d[a-z]*){1}$
Here is an example.

But I don't how to do it for each of the above groups.
I read that for the first example (1 digit and all letters are different) I need to prevent from a repeating char with .*(.).*\1 but I tried: 

^(?=.{5}$)[a-z]*(?:\d[a-z]*)(.*(.).*\1){1}$

It didn't work.

Upvotes: 2

Views: 102

Answers (1)

dawg
dawg

Reputation: 104072

You can use:

/\b(?=[a-zA-Z]*\d[a-zA-Z]*)([a-zA-Z0-9]{5})/

Demo

Add a second \b to reject matching strings longer than 5 characters:

/\b(?=[a-zA-Z]*\d[a-zA-Z]*)([a-zA-Z0-9]{5}\b)/

Demo 2

If you then want to limit to lower case letters:

/\b(?=[a-z]*\d[a-z]*)([a-z0-9]{5}\b)/

Since all combos of the four letters are possible, no further classification is necessary. All the same, all different, some the same.

If you DO want to classify the letters, just capture in Python and add the logic desired.

Based on your example (which it would be helpful to state what is and is not a match for the goal of this question):

/(?=^[a-z]*\d[a-z]*$)(^[a-z0-9]{5}$)/mg

Demo 3

Then if you want to classify into groups, I would just do that in Python:

import re 

st='''\
1aaaa
2aabb
jwzw3
jlwk6
bjkgp
5fm8s
x975t
k88q5
zl796
qm9hb
h6gtf
9rm9p'''

di={}
for m in re.finditer(r'(?=^[a-z]*\d[a-z]*$)(^[a-z0-9]{5}$)', st, re.M):
    di.setdefault(len(set(m.group(1)))-1, []).append(m.group(1))

>>> di
{1: ['1aaaa'], 2: ['2aabb'], 3: ['jwzw3'], 4: ['jlwk6', 'qm9hb', 'h6gtf']}

Upvotes: 2

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