Reputation: 75
I want to print variable in the console. But, I can watch %variable_name%...
This is an example code which can explain my situation.
Set a=%b% and i respect you, answer!
Set b=lolol i'm happy
Echo %a%
What I want::
lolol i'm happy and i respect you, answer!
Results::
%a% and i respect you, answer!
How can i solve this problem?? (I updated my question, sorry...)
Upvotes: 3
Views: 106
Reputation: 56180
First, you need the percent signs in the content of the variable a
. Double them to tell the parser that you want them literal instead of the (current) content of b
.
Then you need another layer of expansion to evaluate %a%
(variable) to %b%
(literal with the percent signs) then to evaluate that %b%
to the content of b
:
Set a=%%b%% and i respect you, answer!
Set b=lolol i'm happy
call Echo %a%
Upvotes: 4