CODEWITHSUNDEEP
pythonlistdictionarytupleslist-comprehension
Kris
Kris

Reputation: 327

Dictionary with multiple values to tuple

I have a dictionary with multiple values follows: 

dict_a = {1: {'a':1, 'b':2, 'c':3},  2:{'a': 4, 'b':5, c:'6'}}

.
I want the result as such: 

[('a',(1,4)),('b',(2,5)), ('c',(3,6))]

I wrote a code: 

for keys, values in dict_a:  
    for k, v in values:  
        print(v)

But the result comes like ('a',1),('b',2).... I am little stuck here. Can anyone help me on this please!!!

Upvotes: 2

Views: 1902

Answers (2)

jpp
jpp

Reputation: 164783

You can use a list comprehension:

dict_a = {1: {'a':1, 'b':2, 'c':3}, 2: {'a':4, 'b':5, 'c':6}}

res = [(k, tuple(d[k] for d in dict_a.values())) for k in dict_a[1]]

[('a', (1, 4)), ('b', (2, 5)), ('c', (3, 6))]

Assumes:

  1. dict_a is ordered by outer key, which may be automatic in Python 3.6+. Otherwise, use collections.OrderedDict.
  2. The keys in each dictionary value of dict_a are the same.

Upvotes: 3

user3483203
user3483203

Reputation: 51165

Using a collections.defaultdict:

Setup

from collections import defaultdict    
dct = defaultdict(tuple)

for _, v in dict_a.items():
    for el in v:
        dct[el] += (v[el],)

print(list(dct.items())


[('a', (1, 4)), ('b', (2, 5)), ('c', (3, '6'))]

Upvotes: 1

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