Reputation: 1725
Given my models
class CUSTOMER():
ID = db.Column(db.String(12), primary_key=True)
PotentialCustomer = db.Column(db.String(12))
FirstNameEn = db.Column(db.String(35))
LastNameEn = db.Column(db.String(35))
FirstNameKh = db.Column(db.String(35))
LastNameKh = db.Column(db.String(35))
Salutation = db.Column(db.String(4))
Gender = db.Column(db.String(6))
DateOfBirth = db.Column(db.String(10))
CountryOfBirth = db.Column(db.String(2))
Nationality = db.Column(db.String(2))
ProvinceOfBirth = db.Column(db.String(3))
I would like to get a list column name of model CUSTOMER()
so that I could loop through that column name?
I tried to surfed around via google but has no clue how I can archive that?
Any idea I can archive that? Thanks
Upvotes: 3
Views: 15050
Reputation: 817
You are searching for column_descriptions()
.
When you use column_descriptions()
, you would get the metadata about the columns which would be returned in the query.
In your case:
customer_alias = aliased(CUSTOMER, name='customer2')
#If you want a single field (CUSTOMER.ID)
customer_query = con.query(CUSTOMER, CUSTOMER.ID, customer_alias)
customer_query.column_descriptions
[
{
'name':'CUSTOMER',
'type':CUSTOMER,
'aliased':False,
'expr':CUSTOMER,
'entity': CUSTOMER
},
{
'name':'ID',
'type':String(),
'aliased':False,
'expr':CUSTOMER.ID,
'entity': CUSTOMER
},
{
'name':'customer2',
'type':CUSTOMER,
'aliased':True,
'expr':customer_alias,
'entity': customer_alias
}
]
But, in case you want all the keys, you should:
#we just want one field:
query = session.query(CUSTOMER).filter_by(id=1)
#then:
conn.execute(query).keys()
And you will get the column names ['id',PotentialCustomer, FirstNameEN...]
Another options:
CUSTOMER.__table__.columns.keys()
CUSTOMER.metadata.columns.keys()
Upvotes: 6