CODEWITHSUNDEEP
javascriptnode.js
user9518022
user9518022

Reputation:

Wait for two async functions to finish then continue in Node.js

I'm working on an application in Node.js where I'm calling an async function twice, and assign the value to a global variable.

The issue is that I want to use the result of the two calls to do something else, but this something else doesn't wait for the result to be assigned.

Here's my code:

var a;
var b;

let x = 'abcd';
foo(x).then(data=>{
    a = data;
});

x = 'efgh';
foo(x).then(data=>{
    b = data;
});

console.log(a + b); // for example

How can I wait for the two functions to finish, before executing a + b?

Upvotes: 8

Views: 15549

Answers (3)

michaelitoh
michaelitoh

Reputation: 2340

As foo returns a Promise you should mark your function as asyncronus with async keyword and wait for the foo function to respond with the await keyword.

 async function someFunction(){   
  let x = 'abcd';
  let a = await  foo(x);

  x = 'efgh';
  let b = await foo(x);
  console.log(a + b)
}

Upvotes: 5

nikos fotiadis
nikos fotiadis

Reputation: 1085

Instead of using .then() you can use await. So this:

foo(x).then(data=>{
    a = data;
});

would be like this:

a = await foo(x);

Same goes for the other function. This will cause your execution to wait until the functions return. Notice however that in order to use await you would have to wrap the statement that uses it, or even better the whole block, in a function that is declared as aync.You can find more on how to use async here.

Upvotes: 0

Luca Kiebel
Luca Kiebel

Reputation: 10096

You can use Promise.all here, to wait for the two promises and then work with their data:

let promises = [];
let x = 'abcd';
promises.push(foo(x))

x = 'efgh';
promises.push(foo(x))

Promise.all(promises).then(([a, b]) => {
  console.log(a, b); // for example
});


function foo(d) {
  return Promise.resolve({somePaddingData:"", d});
}

Upvotes: 9

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