CODEWITHSUNDEEP
javadateparsinglocalizationjava-time
Artsiom
Artsiom

Reputation: 47

What's wrong with Java date parsing code?

This Java code:

LocalDate.parse("12 Сен 2018", DateTimeFormatter.ofLocalizedDate(FormatStyle.MEDIUM).withLocale(new Locale("ru", "RUS")).ofPattern("dd MMM yyyy"));

leads to the 

java.time.format.DateTimeParseException: Text '12 Сен 2018' could not be parsed at index 3
    at java.base/java.time.format.DateTimeFormatter.parseResolved0(DateTimeFormatter.java:2046)
    at java.base/java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1948)
    at java.base/java.time.LocalDate.parse(LocalDate.java:428)

Tried all of Proper Russian month string translation Java examples - no result.

What's wrong with this code ?

Note: I'm using Java 8

Upd: Tried this on local machine and in online compiler - in online compiler works in local machine - came error.

    Map<Long, String> map = new HashMap<>();
    map.put(1L, "Янв");
    map.put(2L, "Фев");
    map.put(3L, "Мар");
    map.put(4L, "Апр");
    map.put(5L, "Май");
    map.put(6L, "Июн");
    map.put(7L, "Июл");
    map.put(8L, "Авг");
    map.put(9L, "Cен");
    map.put(10L, "Окт");
    map.put(11L, "Ноя");
    map.put(12L, "Дек");
    DateTimeFormatter formatter = new DateTimeFormatterBuilder()
            .appendPattern("dd ")
            .appendText(ChronoField.MONTH_OF_YEAR, map)
            .appendPattern(" yyyy")
            .toFormatter(new Locale("ru", "RU"));       
    System.out.println(LocalDate.parse("12 Cен 2018", formatter));

Upvotes: 2

Views: 238

Answers (3)

ernest_k
ernest_k

Reputation: 45339

There are two problems:

First, ofPattern simply creates a pattern-based formatter, therefore discarding the locale:

DateTimeFormatter.ofLocalizedDate(FormatStyle.MEDIUM)
                 .withLocale(new Locale("ru", "RUS"))
                 .ofPattern("dd MMM yyyy") // <------ static method!!

ofPattern is a static method that simply creates a new DateTimeFormatter instance (see below for a correct way to build it)

Second: the short month name seems incorrect for the pattern:

DateTimeFormatter.ofPattern("dd MMM yyyy")
                 .withLocale(new Locale("ru", "RUS"))
.format(LocalDate.of(2018, 9, 12))

Results in "12 сент. 2018". Java expects сент., not сен.

This works and returns 2018-09-12:

LocalDate.parse("12 сент. 2018", 
         DateTimeFormatter.ofPattern("dd MMM yyyy")
         .withLocale(new Locale("ru", "RUS")))

Upvotes: 1

MohammadReza Samadi
MohammadReza Samadi

Reputation: 11

Hi use this piece of Code :

    Locale locale = new Locale("ru", "RU");
    String pattern = "dd MMM yyyy";
    String date = "03 сен 2017";
    DateTimeFormatter formatter = DateTimeFormatter.ofPattern(pattern, locale);
    LocalDate localDate = LocalDate.parse(date, formatter);
    System.out.println(localDate);

Upvotes: 1

Eugene
Eugene

Reputation: 121088

Well you need to create a custom formatter for this, which is not that complicated (first time knowing russian, become handy answering a stackoverflow question):

Map<Long, String> map = new HashMap<>();
    map.put(1L, "янв");
    map.put(2L, "фев");
    map.put(3L, "мар");
    map.put(4L, "апр");
    map.put(5L, "май");
    map.put(6L, "июн");
    map.put(7L, "июл");
    map.put(8L, "авг");
    map.put(9L, "сен");
    map.put(10L, "окт");
    map.put(11L, "ноя");
    map.put(12L, "дек");
    DateTimeFormatter fmt = new DateTimeFormatterBuilder()
            .appendPattern("dd ")
            .appendText(ChronoField.MONTH_OF_YEAR, map)
            .appendPattern(" yyyy")
            .toFormatter(new Locale("ru"));

 System.out.println(LocalDate.parse("12 сен 2018", fmt)); // 2018-09-12

Upvotes: 2

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