CODEWITHSUNDEEP
sqloracle-databaseanalytic-functions
dk96m
dk96m

Reputation: 331

Oracle get row where column value changed

Say I have a table, something like

ID     CCTR    DATE
-----  ------  ----------
1      2C      8/1/2018
2      2C      7/2/2018
3      2C      5/4/2017
4      2B      3/2/2017
5      2B      1/1/2017
6      UC      11/23/2016

There are other fields, but I made it simple. So I create a query where i have the date in descending order. I was to return the row where there was a change in CCTR. So in this case it would return ID 4. Basically i want to find the previous value of CCTR before it changed, in this case from 2B to 2C.

How do I do this? Ive tried to google it, but can't seem to find the right method.

Upvotes: 3

Views: 5614

Answers (2)

Barbaros Özhan
Barbaros Özhan

Reputation: 65228

You may use first_value analytic function to detect the changes in CCTR column :

select fv as value, cctr
  from 
(
  with t(ID,CCTR) as
  (
   select 1,'2C' from dual union all
   select 2,'2C' from dual union all
   select 3,'2C' from dual union all
   select 4,'2B' from dual union all
   select 5,'2B' from dual union all
   select 6,'UC' from dual
  ) 
  select id, cctr, first_value(id) over (partition by cctr order by id ) fv
    from t
  order by id
)  
where id = fv;

VALUE  CCTR
-----  ----
  1     2C
  4     2B
  6     UC

Rextester Demo

Upvotes: 2

The Impaler
The Impaler

Reputation: 48770

You can use the LAG() window function to peek at the previous row and compare it. If your data is:

create table t2 (
  id number(6),
  cctr varchar2(10),
  date1 date
);

insert into t2 (id, cctr, date1) values (1, '2C', date '2018-08-01');
insert into t2 (id, cctr, date1) values (2, '2C', date '2018-07-02');
insert into t2 (id, cctr, date1) values (3, '2C', date '2017-05-04');
insert into t2 (id, cctr, date1) values (4, '2B', date '2017-03-02');
insert into t2 (id, cctr, date1) values (5, '2B', date '2017-01-01');
insert into t2 (id, cctr, date1) values (6, 'UC', date '2016-11-23');

Then the query would be:

select * from t2 where date1 = (
  select max(date1)
    from (
    select 
      id, date1, cctr, lag(cctr) over(order by date1 desc) as prev
      from t2
    ) x  
    where prev is not null and cctr <> prev
);

Result:

ID       CCTR        DATE1    
-------  ----------  -------------------
4        2B          2017-03-02 00:00:00

Upvotes: 4

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