Reputation: 3621
I would like to do a last observation carried forward for a variable, but only up to 2 observations. That is, for gaps of data of 3 or more NA, I would only carry the last observation forward for the next 2 observations and leave the rest as NA.
If I do this with the zoo::na.locf
, the maxgap
parameter implies that if the gap is larger than 2, no NA is replaced. Not even the last 2. Is there any alternative?
x <- c(NA,3,4,5,6,NA,NA,NA,7,8)
zoo::na.locf(x, maxgap = 2) # Doesn't replace the first 2 NAs of after the 6 as the gap of NA is 3.
Desired_output <- c(NA,3,4,5,6,6,6,NA,7,8)
Upvotes: 5
Views: 647
Reputation: 17289
A solution using base R:
ave(x, cumsum(!is.na(x)), FUN = function(i){ i[1:pmin(length(i), 3)] <- i[1]; i })
# [1] NA 3 4 5 6 6 6 NA 7 8
cumsum(!is.na(x))
groups each run of NA
s with most recent non-NA
value.
function(i){ i[1:pmin(length(i), 3)] <- i[1]; i }
transforms the first two NA
s of each group into the leading non-NA
value of this group.
Upvotes: 3
Reputation: 269526
First apply na.locf0
with maxgap = 2
giving x0
and define a grouping variable g
using rleid
from the data.table package. For each such group use ave
to apply keeper
which if the group is all NA replaces it with c(1, 1, NA, ..., NA) and otherwise outputs all 1s. Multiply na.locf0(x)
by that.
library(data.table)
library(zoo)
mg <- 2
x0 <- na.locf0(x, maxgap = mg)
g <- rleid(is.na(x0))
keeper <- function(x) if (all(is.na(x))) ifelse(seq_along(x) <= mg, 1, NA) else 1
na.locf0(x) * ave(x0, g, FUN = keeper)
## [1] NA 3 4 5 6 6 6 NA 7 8
Upvotes: 5