CODEWITHSUNDEEP
javaregex
Ryan
Ryan

Reputation: 21

how to find one character from multiple same character on string by regex

Example: Dear sir, No. Employee is (PM/23333999) 10) i want thank you.(MA/IERPER) i want resigned.

Hi sir,

regex : \d{1,2}+(?:(\)))

result: 10) and 99) and )

What is regex pattern can i using to get result only '10)' from split the string?

Upvotes: 1

Views: 86

Answers (3)

The Scientific Method
The Scientific Method

Reputation: 2436

since you are saying to match only 10) try the following

\d{1,2}+\)(?!.*\d{1,2}+\))

demo and explantion here

Upvotes: 0

Facundo Guerrero
Facundo Guerrero

Reputation: 1

You can do that:

^.*\) (.*) i want t.*$

But, Let's improve the regex:

^.*\([^\)]*\) (\d+\)).*$

Upvotes: 0

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626738

Your pattern is equal to \d{1,2}+\), i.e. your pattern consumes and returns ).

You may use

\d{1,2}(?=\))

where (?=\)) is a positive lookahead that will require the presence of ) but won't return it in the match. Also, note that {1,2}+ here will behave the same as a non-possessive, greedy {1,2} quantifier (as there are no other ways to match the string before )), so no need adding the +.

See the regex demo.

In Java, declare it as

String regex = "\\d{1,2}(?=\\))";

Upvotes: 3

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