CODEWITHSUNDEEP
pythonregex
vieroli
vieroli

Reputation: 376

Python condition with regex

I have a file with those data : 

PAS_BEGIN_0009999
    T71_MANUFACTURER_4=98
    T71_COLOR_ID_7=000
    T71_OS_7=08
PAS_END_0009999

PAS_BEGIN_0009996
    T72_VAS_SERVICE_IDENTIFIER_6=
    T72_ORDER_NB_7=0003
    T72_TECHNOLOGY_7=01
PAS_END_0009996

TPV_BEGIN
    PAS_20819001=3600000 
TPV_END

How can I simply isolate content betweenPAS_BEGIN_0009996 and PAS_BEGIN_0009996

Here is a link for the example : https://regexr.com/3vmeq

It finds something, but my python code doesn't find anything..

if re.match("PAS_BEGIN_0009999([\S\s]*)PAS_END_0009999", line):
    data.append(line)
    print(line)

Can anyone help me on this ? Thanks

Upvotes: 1

Views: 41

Answers (1)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626738

You are reading a text file line by line, but your expected match is located on several lines. You need to read the whole file into a variable, then run a regex like yours, or, better, a pattern like a.*?b with re.DOTALL option so that . could match line break chars.

So, you may use something like

import re
fpath = 'your_file_path.txt'
data = ''
pattern=r'PAS_BEGIN_0009999(.*?)PAS_END_0009999'
with open(filepath, "r") as f:
    contents = f.read()
    m = re.search(pattern, contents)
    if m:
        data = m.group(1) # or `.group() if you need to include PAS_BEGIN_0009999 and PAS_END_0009999

If you need to find multiple occurrences, replace the re.search part (all lines after contents) with

data = re.findall(pattern, contents)

See the regex demo

Upvotes: 1

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