CODEWITHSUNDEEP
c++arraysstringtemplateschar
qing
qing

Reputation: 67

Sort char array using sort function c++

I am trying to limit user input into alphabet only, then sort all the character in ascending order.

build messages error: no matching function for call to 'std::__cxx11::basic_string::basic_string(char&)'

This is my header

#include <iostream>
#include <string.h>
#include <conio.h>
#include <stdio.h>
#include <regex>

should i convert the char into string then convert back to char for my following code ?

string Sortstr (str[mlength]);
sort(Sortstr.begin(), Sortstr.end());

getting this 2 line error.

int mlength = 100;
int main() {
    char str[mlength];
    int length;

    cout << "Please enter a c-string: ";
    cin.getline(str,mlength,'\n');
    regex pass1("^[a-zA-Z]+");
    while(!regex_match(str,pass1)) {
         cout<<"Error"<<endl;
         cout << "Please enter a c-string: ";
         cin.getline(str,mlength,'\n');
    }
    string Sortstr (str);
    sort(str, str + strlen(str));
}

Upvotes: 2

Views: 2019

Answers (2)

sebrockm
sebrockm

Reputation: 6002

In this line

string Sortstr (str[mlength]);

you are using the index operator on a char array which gives you one single char. So, you are passing one single char to the string constructor. This constructor does not exist, hence the error. Even if it existed, you do not want to pass one single char but the entire char array.

What you want is this:

string Sortstr (str);

Upvotes: 2

john
john

Reputation: 87957

Why not just sort str?

sort(str, str + strlen(str));

There's no reason you can't sort an array directly. Just pass pointers to the first and one-past-the-end elements of your array to sort. In this case adding strlen gets a pointer to the effective end of your array.

Upvotes: 3

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