Reputation: 172
I have table like this
create table aaa (id int not null, data varchar(50), numb int);
with data like this
begin
for i in 1..30 loop
insert into aaa
values (i, dbms_random.string('L',1),dbms_random.value(0,10));
end loop;
end;
now im making this
select a.id, a.data, a.numb,
count(*) over (partition by a.numb order by a.data) count,
b.id, b.data,b.numb
from aaa a, aaa b
where a.numb=b.numb
and a.data!=b.data
order by a.data;
and i want to update every row where those numbers are the same but with different letters, and in result i want to have new data with more than one letter (for example in data column- "a c d e"), i just want to create concatenation within. How can i make that? the point is to make something like group by for number but for that grouped column i would like to put additional value.
that is how it looks like in begining
id | data |numb
1 q 1
2 z 8
3 i 7
4 a 2
5 q 4
6 h 1
7 b 9
8 u 9
9 s 4
That i would like to get at end
id | data |numb
1 q h 1
2 z 8
3 i 7
4 a 2
5 q s 4
7 b u 9
Upvotes: 0
Views: 65
Reputation: 31648
Try this
SELECT MIN(id),
LISTAGG(data,' ') WITHIN GROUP(
ORDER BY data
) data,
numb
FROM aaa GROUP BY numb
ORDER BY 1
Upvotes: 1
Reputation: 14848
This selects 10 random strings 1 to 4 letters long, letters in words may repeat:
select level, dbms_random.string('l', dbms_random.value(1, 4))
from dual connect by level <= 10
This selects 1 to 10 random strings 1 to 26 letters long, letters do not repeat and are sorted:
with aaa(id, data, numb) as (
select level, dbms_random.string('L', 1),
round(dbms_random.value(0, 10))
from dual connect by level <= 30)
select numb, listagg(data) within group (order by data) list
from (select distinct data, numb from aaa)
group by numb
Upvotes: 0