CODEWITHSUNDEEP
java
Smile.Hunter
Smile.Hunter

Reputation: 252

ordinary expression

Scanner kb = new Scanner(System.in);

System.out.print(">> ");
String line = kb.nextLine();

line = line.trim();
int i = 0;

do {
  int j = i;
  while ((!line.substring(j, j + 1).equals(" ")) && (j < line.length())) {
  //while ((j < line.length())&&(!line.substring(j, j + 1).equals(" "))) {
    j++;
  }
  System.out.println("-> " + line.substring(i, j));
  i = j;
  while ((line.substring(i, i + 1).equals(" "))&&(i<line.length())) {
  //while ((i < line.length()) && (line.substring(i, i + 1).equals(" "))) {

    i++;
  }
}while (i < line.length());

why expression ....

while ((!line.substring(j, j + 1).equals(" ")) && (j < line.length()))

not equal with

while ((j < line.length())&&(!line.substring(j, j + 1).equals(" ")))

Upvotes: 0

Views: 119

Answers (1)

LazyCubicleMonkey
LazyCubicleMonkey

Reputation: 1243

Because the string could be of length 0 in which case you will get an ArrayIndexOutOfBounds exception.

Upvotes: 1

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