CODEWITHSUNDEEP
javascriptcomparisondate-comparison
user2587676
user2587676

Reputation: 127

How can you compare "week-year" value in JS?

For example, I have the following String values in week-year format: 

// week-year
"8-18" < "9-18"   // returns true
"8-18" < "10-18"  // returns false but should return true
"8-18" < "4-18"   // returns false but should be true

I have to sort out an array of arrays with "week-year" values for scheduling purposes. Currently I'm using array.sort to accomplish this:

var results = [
  [ 
    { weekyear:"4-18" } 
  ], 
  [
    { weekyear:"5-18" }
  ], 
  [
    { weekyear: "1-19" }
  ] ... ]

results.sort((function (index) { // Sort based on Week-Year in descending order 
  return function (a, b) {
    return (a[index].weekyear === b[index].weekyear ? 0 : (a[index].weekyear< b[index].weekyear ? -1 : 1));
  };
})(0));

Is there any way I can perhaps modify the week-year value into a numerical value that allows sorting?

The above sort should give me in order: 

"1-19" , "5-18" , "4-18"

Upvotes: 1

Views: 280

Answers (1)

Nina Scholz
Nina Scholz

Reputation: 386560

You could create a formatted string where the year comes first, followed by a padded week, which could be compared as string.

function getYearWeek(weekYear) {
    return weekYear
        .split('-')
        .map(s => s.padStart(2, '0'))
        .reverse()
        .join('-W');
}

var results = [{ weekyear: "4-20" }, { weekyear: "5-18" }, { weekyear: "4-18" }, { weekyear: "1-19" }];

console.log(getYearWeek("8-18") < getYearWeek("9-18"));  // true
console.log(getYearWeek("8-18") < getYearWeek("10-18")); // true
console.log(getYearWeek("8-18") < getYearWeek("4-18"));  // false

results.sort((a, b) => 
    getYearWeek(a.weekyear).localeCompare(getYearWeek(b.weekyear)));

console.log(results);
.as-console-wrapper { max-height: 100% !important; top: 0; }

Upvotes: 1

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