Reputation: 142
I creted a loop checking number of characters length with conditions but sadly it's not properly working, with approriate no. of loops but not reading the next line, I want to post the result in a MsgBox, but when I use the msgbox inside the loop I will get a msgbox for every result found or only one msgbox with one result.
What I would like is to display every result in 1 msgbox with a line vbNewLine after each result.
Below is my code:
Public Sub Rs()
Dim Text As String
Dim NumChar As String
Dim i As Integer
Dim NumRows As Long
Application.ScreenUpdating = False
'Get Cell Value
Text = Range("B2").Value
'Get Char Length
NumChar = Len(Text)
NumRows = Range("B2", Range("B2").End(xlDown)).Rows.Count
Range("B2").Select
For i = 1 To NumRows
'Character length validation
If Len(Text) <= 15 Then
MsgBox Chr(149) & " SVC_DESC " & Text & " has " & NumChar & " characters " & " and it's Valid !" & vbNewLine
Else
MsgBox Chr(149) & " SVC_DESC " & Text & " has " & NumChar & " characters " & " and Exceeded allowable number of characters!" & vbNewLine
End If
Next i
Application.ScreenUpdating = True
End Sub
Upvotes: 1
Views: 7509
Reputation:
Build a string through concatenation and display the strings after exiting the loop.
Public Sub Rs()
Dim Text As String
Dim NumChar As String
Dim i As Integer
Dim NumRows As Long
dim msg1 as string, msg2 as string
Application.ScreenUpdating = False
'Get Cell Value
Text = Range("B2").Value
'Get Char Length
NumChar = Len(Text)
NumRows = Range("B2", Range("B2").End(xlDown)).Rows.Count
Range("B2").Select
For i = 1 To NumRows
'Character length validation
If Len(Text) <= 15 Then
msg1 = msg1 & Chr(149) & " SVC_DESC " & Text & " has " & NumChar & " characters " & " and it's Valid !" & vbLF
Else
msg2 = msg2 & Chr(149) & " SVC_DESC " & Text & " has " & NumChar & " characters " & " and Exceeded allowable number of characters!" & vbLF
End If
Next i
Application.ScreenUpdating = True
if cbool(len(msg1)) then
msg1 = left(msg1, len(msg1)-1)
MsgBox msg1
end if
if cbool(len(msg2)) then
msg2 = left(msg2, len(msg2)-1)
MsgBox msg2
end if
End Sub
A MsgBox uses Chr(10) aka vbLF for new lines; vbNewLine is overkill.
Upvotes: 1
Reputation: 43585
Assign the new text to a string variable and display the string variable outside the loop:
Option Explicit
Sub TestMe()
Dim i As Long
Dim displayText As String
For i = 1 To 3
displayText = displayText & vbCrLf & i
Next i
MsgBox displayText
End Sub
Upvotes: 2