CODEWITHSUNDEEP
python
Sc-python-leaner
Sc-python-leaner

Reputation: 259

Searching in a list to see if an item contains part of the word

Not seeing my answer so I'm going to explain what I'm looking to do. I need to break some data out of a url, some of the urls have the word limit in the followed by a guid. What I want to do is see if the word is in any part of the item in the list.

I want to iterate through the list items and if the item contains the word limit I want to get the next 33 characters

Here is an example of the list:

limits = ['limit=5e8f0dc0-4074-481d-a12c-5d3a70406ad7&location=d877f1f9-fae3-4f39-82ca-499ec8a7a0d2', 'location=d877f1f9-fae3-4f39-82ca-499ec8a7a0d2', 'sourceLimitAllocationOid=212a7e22-aafd-40e3-9684-621dae6708af&sourceUnits=5000&sourceUnitOfMeasureCode=TON&tragetUnitOfMeasureOid=1bec1009-90d3-de11-9251-001d092afdd0&targetLimitCommodityOid=7e7a1112-b7c7-4563-9bd4-702e14b139f4', '', 'limit=5e8f0dc0-4074-481d-a12c-5d3a70406ad7&location=2e12899b-e84d-4b1a-8b89-faced0771efc', '', 'location=2e12899b-e84d-4b1a-8b89-faced0771efc', 'sourceLimitAllocationOid=bfa24508-a4e3-4138-8d29-7e9b7c1ea559&sourceUnits=3000000&sourceUnitOfMeasureCode=BU&tragetUnitOfMeasureOid=1bec1009-90d3-de11-9251-001d092afdd0&targetLimitCommodityOid=7e7a1112-b7c7-4563-9bd4-702e14b139f4', '', '', 'limit=c0ba884c-800b-4174-8374-0bc5515f8282&location=b3d785e6-4d0c-460b-8e2c-1f32732a1a20', 'location=b3d785e6-4d0c-460b-8e2c-1f32732a1a20']

Upvotes: 1

Views: 47

Answers (2)

Woody1193
Woody1193

Reputation: 7980

According to this tutorial, you can do this:

offset = len("limit")
limit = ""
for item in limits:
    index = item.find("limit")
    if (index != -1):
        limit = item[ (limit + offset + 1): (limit + offset + 34) ]
        break

There's a couple of things going on here on top of what you asked for. First, I assumed that there's only one string with limit in it. If not, remove the break statement and make limit be a list with the assignment changed to an append. Second, I assumed you didn't want to take the = from the string so I'm actually adding one to the start and end to do that. Alternatively, you could just remove the first character later if that's what you want to do.

I hope this helps.

Upvotes: 1

drkostas
drkostas

Reputation: 527

Try this:

import re
limits = ['limit=5e8f0dc0-4074-481d-a12c-5d3a70406ad7&location=d877f1f9-fae3-4f39-82ca-499ec8a7a0d2', 'location=d877f1f9-fae3-4f39-82ca-499ec8a7a0d2', 'sourceLimitAllocationOid=212a7e22-aafd-40e3-9684-621dae6708af&sourceUnits=5000&sourceUnitOfMeasureCode=TON&tragetUnitOfMeasureOid=1bec1009-90d3-de11-9251-001d092afdd0&targetLimitCommodityOid=7e7a1112-b7c7-4563-9bd4-702e14b139f4', '', 'limit=5e8f0dc0-4074-481d-a12c-5d3a70406ad7&location=2e12899b-e84d-4b1a-8b89-faced0771efc', '', 'location=2e12899b-e84d-4b1a-8b89-faced0771efc', 'sourceLimitAllocationOid=bfa24508-a4e3-4138-8d29-7e9b7c1ea559&sourceUnits=3000000&sourceUnitOfMeasureCode=BU&tragetUnitOfMeasureOid=1bec1009-90d3-de11-9251-001d092afdd0&targetLimitCommodityOid=7e7a1112-b7c7-4563-9bd4-702e14b139f4', '', '', 'limit=c0ba884c-800b-4174-8374-0bc5515f8282&location=b3d785e6-4d0c-460b-8e2c-1f32732a1a20', 'location=b3d785e6-4d0c-460b-8e2c-1f32732a1a20']

for el in limits:
    a = re.search(r'\b(limit)\b', el)
    if a is not None:
        ind = a.start()
        print(el[ind+5:ind+38])

Upvotes: 2

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