Reputation: 449
I have a 2D array of doubles for a problem using dynamic programming. What I want to do is below (f is any function operating on the variable "size" and returns an int) :
void myFunction(int size){
double myArr[size][f(size)];
helperFunction(size, myArr);
}
void helperFunction(int size, double[][] myArr){
//do something
}
However this code is obviously a mashup of java and c++. How would I accomplish this in c++?
Upvotes: 0
Views: 103
Reputation: 77
Highly recommend using vectors as alternative to dynamic arrays. Vectors have a bad reputation in java, but in c++ they're the way to go. Demonstrating "a" c++ way of accomplishing this, using both "new" allocation and vectors. Warning: unlike java, primitive arrays in c++ will require you to keep track of array sizes; all inner arrays as well.
#include <iostream>
#include <vector>
class Test{
private:
double **myArray;//Primitive 2d array; suggest using 2d vector.
std::vector<std::vector<double>> myVector;//Alternative vector.
std::vector<int> col;//Using vector for myArray sizes; where sizes = inner array size.
int size;//Required with primitive dynamic array; size of array.
public:
Test(){
myArray = 0;//c++ initialization before reading; safety.
size = 0;//c++ "" "" ""
}
~Test(){
flushArray();//Flush all data on destructor.
}
void flushArray(){//Empties 2d array and set it to 0.
//Flush of primitive 2d array.
for(int i = 0; i < size; ++i) {//Needs to delete every new data created
delete []myArray[i];//Freeing memory for inner node.
}
delete []myArray;//Freeing memory for outer node.
myArray = 0;//Setting pointer to 0;
size = 0;//Setting size to 0;
col.clear();//Flush for column vector: easy.
//vector is self maintained and will clear itself on destructor; exception: "new" DATA.
}
void myFunction(int size) {
if(this->size != 0) {//If there is already data...
flushArray();//Flush Array;
}
this->size = size;//Require size to free during next call.
myArray = new double*[size];//Create new array of nothings with a size of "size".
for(int i = 0; i < size; ++i) {
//Traversing through array and adding an array of doubles.
myArray[i] = new double[f(size,false)];//New DATA can be implicit
}
}
void otherFunction(int size) {
myVector.clear();//Flush Vector;
myVector.resize(size);//Automated dynamic sizing
for(auto it = myVector.begin(); it != myVector.end(); ++it) {
it->resize(f(size,true));
}
}
int f(int size, bool isVector) {
//.., do something.
if(isVector) {
return size;//Whatever int you were meant to return.
}
//Keep track of cols, maybe they'll vary
col.push_back(size);//it might be (size+i)... Required for dynamic array.
return col.back();//Return the intended size.
}
void printArraySize() {
for(int i = 0; i < size; ++i) {
std::cout<<"myArray["<<i<<"] has "<<col[i]<<" elements."<<std::endl;
}
}
void printVectorSize() {
//Using a counter, chose to use primitive for-loop.
for(int i = 0; i < myVector.size(); ++i) {
std::cout<<"myVector["<<i<<"] has "<<myVector[i].size()<<" elements. "<<std::endl;
}
}
};
int main()
{
Test test;
test.myFuntion(10);
test.otherFunction(10);
test.printArraySize();
test.printVectorSize();
return 0;
}
Printing results to show size:
myArray[0] has 10 elements.
myArray[1] has 10 elements.
myArray[2] has 10 elements.
myArray[3] has 10 elements.
myArray[4] has 10 elements.
myArray[5] has 10 elements.
myArray[6] has 10 elements.
myArray[7] has 10 elements.
myArray[8] has 10 elements.
myArray[9] has 10 elements.
myVector[0] has 10 elements.
myVector[1] has 10 elements.
myVector[2] has 10 elements.
myVector[3] has 10 elements.
myVector[4] has 10 elements.
myVector[5] has 10 elements.
myVector[6] has 10 elements.
myVector[7] has 10 elements.
myVector[8] has 10 elements.
myVector[9] has 10 elements.
Process returned 0 (0x0) execution time : 0.011 s
Press any key to continue.
Basically with vectors: your data, their sizes, and lifespan are managed for you; exception vector of pointers to "new" data. Whereas in a primitive dynamic arrays, you'll have to keep track of your arrays sizes (all of them) and delete your data/arrays when done with.
Edit: Minor spelling check.
Upvotes: 1