CODEWITHSUNDEEP
swiftenumsoutputenumeration
Guillaume
Guillaume

Reputation: 191

Create an enum with parameter

I have some Outputs in my code so I regrouped all that with an Enum String.

The problem is that I have some Outputs containing variable.

Is It possible to create an Enum who takes variable ?

Exemple with this string

print("The name of the Team is \(team.name)")

I wanted to do something like that:

enum Exemple: String {
    case TEAM_NAME(name: String) = "The name of the Team is \(name)"}

print(Exemple.TEAM.NAME("Team 1").rawvalue)

Thank you

Upvotes: 1

Views: 3464

Answers (3)

AlexSmet
AlexSmet

Reputation: 2161

You can define an instance method or computed property for enum that will return a string value in depend of enumeration case and associated value. See example for playground.

enum Example {
    case firstItem
    case secondItem(withText: String)

    var stringValue: String {
        switch self {
        case .firstItem: return "Simple string"
        case .secondItem(withText: let text): return "String with additional text: \(text)"
        }
    }
}

let myEnumItem: Example = .secondItem(withText: "Test")
let text = myEnumItem.stringValue

Upvotes: 1

Azzaknight
Azzaknight

Reputation: 167

It is not possible for Enum to have both raw value and associated value. I think you can get by with the associated value. Without the raw value the enum still can provide you enough information to compose the message

Upvotes: 0

inokey
inokey

Reputation: 6170

It's possible to have an enum with associated values for cases. But in order to get the output you're looking for you will need a function.

enum Example {

    case teamName(name: String)
    case teamId(id: Int)

    func printName() {
        switch self {
        case .teamName(name: let name):
            print(name)
        default:
             break
        }
    }
}

let team = Example.teamName(name: "team1")
team.printName() // prints team1

Upvotes: 1

Related Questions