Reputation: 4189
I have to apply two long sequences of chained transitions which differ mainly in the order of transitions on some elements, and I'm looking for a compact way to code. Suppose (only as a toy example) that I have two circles and I have to apply the following colors to the first one:
orange
-> purple
-> blue
-> yellow
;
and the following colors to the second one:
blue
-> yellow
-> orange
-> purple
.
I've tried with the code below (fiddle here), but it doesn't work. Which is the most compact way to achieve this?
var svg = d3.select('svg');
var dataSet = [20, 20];
var group=svg.append("g");
var circles = group.selectAll('circle')
.data(dataSet)
.enter()
.append('circle')
.attr("r",function(d){ return d })
.attr("cx",function(d, i){ return i * 100 + 50 })
.attr("cy",50)
.attr("fill",'black');
var t1 = d3
.transition()
.duration(1000)
.attr("fill","orange")
.transition()
.duration(1000)
.attr("fill","purple");
var t2 = d3
.transition()
.duration(1000)
.attr("fill","blue")
.transition()
.duration(1000)
.attr("fill","yellow");
group.select(":nth-child(1)")
.transition(t1).transition(t2);
group.select(":nth-child(2)")
.transition(t2).transition(t1);
Upvotes: 2
Views: 142
Reputation: 38161
There are a multitude of ways to achieve this. As noted in the other answer, using a function for this will keep your code compact. Personally I tend to use the transition's end event to trigger the next transition from within the transition function.
The general form for this sort of function is as follows:
function transition() {
// .... optional logic here.
d3.select(this) // do transition:
.transition()
.attr("fill", ... )
.on("end", transition); // and repeat.
}
It can be called with selection.each(transition)
One approach to managing the current color/transition in the cycle is to use a custom attribute. Below I use .attr("i")
to keep track:
var data = [
["orange","purple","blue","yellow"],
["blue","yellow","orange","purple"]
];
var svg = d3.select("svg");
var circles = svg.selectAll()
.data(data)
.enter()
.append("circle")
.attr("r", 20)
.attr("cx", function(d,i) { return i * 50 + 50; })
.attr("cy", 50)
.attr("fill", function(d) { return d[0]; })
.attr("i",0)
.each(transition);
// cycle endlessly:
function transition() {
var selection = d3.select(this);
// keep track of current value:
var i = selection.attr("i")
selection
.attr("i",i = ++i%4)
.transition()
.duration(1000)
.attr("fill", function(d) { return d[i] })
.on("end", transition);
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/4.10.0/d3.min.js"></script>
<svg width="500" height="300"></svg>
If you have transitions that differ only in order (start point), you can modify the above approach a bit:
var data = [50,75,100,125,150,175,200,225];
var colors = ["orange","purple","blue","yellow"];
var svg = d3.select("svg");
var circles = svg.selectAll()
.data(data)
.enter()
.append("circle")
.attr("r", 20)
.attr("cx", function(d) { return d; })
.attr("cy", 50)
.attr("fill", function(d,i) { return colors[i%4]; }) // set start fill
.attr("i", function(d,i) { return i%4; }) // record start position.
.each(transition);
function transition() {
var selection = d3.select(this);
var i = selection.attr("i");
i = ++i%colors.length;
selection.transition()
.duration(1000)
.attr("i",i)
.attr("fill", colors[i])
.on("end", transition);
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/4.10.0/d3.min.js"></script>
<svg width="500" height="300"></svg>
First one I use color sets as the datum, second one I just use position accessing the color with the i
attribute
The above methods use a custom attribute, but we can use the datum too. This allows us a bit more D3 familiarity in some ways.
For example, we can have a property called color and increment that while setting the fill on each transition (again assuming we have a colors array and each circle starts at a different point on it):
function transition() {
d3.select(this).transition()
.duration(1000)
.attr("fill", function(d) { return colors[++d.color%colors.length]; })
.on("end", transition);
}
var data = d3.range(8).map(function(d) { return {x: d*25+50}; })
var colors = ["orange","purple","blue","yellow"];
var svg = d3.select("svg");
var circles = svg.selectAll()
.data(data)
.enter()
.append("circle")
.attr("r", 20)
.attr("cx", function(d) { return d.x; })
.attr("cy", 50)
.attr("fill", function(d,i) { return colors[i%4]; }) // set start fill
.each(function(d,i) { d.color = i%4; }) // record start position.
.each(transition);
function transition() {
d3.select(this).transition()
.duration(1000)
.attr("fill", function(d) { return colors[++d.color%colors.length]; })
.on("end", transition);
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/4.10.0/d3.min.js"></script>
<svg width="500" height="300"></svg>
If you want the transitions to repeat x times, or even have all end on the same color, we can do that fairly easily too by adding a new property to the datum to track cycles completed:
var data = d3.range(8).map(function(d) { return {x: d*25+50}; })
var colors = ["orange","purple","blue","yellow"];
var svg = d3.select("svg");
var circles = svg.selectAll()
.data(data)
.enter()
.append("circle")
.attr("r", 20)
.attr("cx", function(d) { return d.x; })
.attr("cy", 50)
.attr("fill", function(d,i) { return colors[i%4]; }) // set start fill
.each(function(d,i) { d.color = d.start = i%4; }) // record start position.
.each(transition);
var n = 8; // n cycles
function transition() {
d3.select(this).transition()
.duration(1000)
.attr("fill", function(d) { return colors[++d.color%colors.length]; })
.on("end", function(d) { if(d.color - d.start < n) transition.apply(this); else return null; });
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/4.10.0/d3.min.js"></script>
<svg width="500" height="300"></svg>
There are lazier ways that destructively modify the datum (or portions of it), such as using shift in this transition cycle that can only run once:
var data = [
["orange","purple","blue","yellow"],
["blue","yellow","orange","purple"]
];
var svg = d3.select("svg");
var circles = svg.selectAll()
.data(data)
.enter()
.append("circle")
.attr("r", 20)
.attr("cx", function(d,i) { return i * 50 + 50; })
.attr("cy", 50)
.attr("fill", function(d) { return d.shift(); })
.each(transition);
function transition() {
var selection = d3.select(this);
if(selection.datum().length) {
selection.transition()
.duration(1000)
.attr("fill", function(d) { return d.shift() })
.on("end", transition);
}
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/4.10.0/d3.min.js"></script>
<svg width="500" height="300"></svg>
You might see that none of my snippets use child selectors: this can be avoided by custom attributes, datum properties, or more simply, using .attr("fill",function(d,i){
in the transition itself to differentiate odd and even elements. I have nothing against those selectors though, it just requires additional selections to be made.
Upvotes: 3
Reputation: 9520
If you create a function to apply the transition, you can compact your code down a fair bit:
/**
* Apply a transition with the appropriate delay to a selection
*
* @param sel: a d3 selection
* @param fill: the fill colour
* @param position: the position of the colour in the set of transitions
*/
function tr(sel, fill, position) {
sel.transition()
.duration(1000)
.delay(1000 * position)
.ease(d3.easeLinear)
.attr("fill", fill);
}
// example of use:
tr(group.select(":nth-child(1)"), 'blue', 0)
tr(group.select(":nth-child(2)"), 'red', 2)
In action:
function tr(sel, fill, pos) {
sel.transition()
.duration(1000)
.delay(1000 * pos)
.ease(d3.easeLinear)
.attr("fill", fill);
}
var svg = d3.select('svg');
var dataSet = [20, 20];
var group = svg.append("g");
var circles = group.selectAll('circle')
.data(dataSet)
.enter()
.append('circle')
.attr("r",function(d){ return d })
.attr("cx",function(d, i){ return i * 100 + 50 })
.attr("cy",50)
.attr("fill",'black');
var colors = {
1: [ 'orange', 'purple', 'blue', 'yellow' ],
2: [ 'deepskyblue', 'deeppink', 'goldenrod', 'magenta']
};
Object.keys(colors).forEach(function(ix){
var el = group.select(":nth-child(" + ix + ")");
colors[ix].forEach( function(c,i) { tr(el, c, i); });
})
<script src="https://d3js.org/d3.v4.min.js"></script>
<svg></svg>
Upvotes: 2